Question

In: Statistics and Probability

National data indicates that​ 35% of households own a desktop computer. In a random sample of...

National data indicates that​ 35% of households own a desktop computer. In a random

sample of 570​ households, 40% owned a desktop computer. Does this provide enough

evidence to show a difference in the proportion of households that own a​ desktop?

Identify the appropriate null and alternative hypotheses.

A. H0: p= 0.35 Ha​: p ≠ 0.35

B. H0​: p​ = 0.40     Ha​:p​ > 0.40

C. H0​:p​ = 0.35     Ha​:p​ < 0.35

D. H0​:p​ = 0.40     Ha​:p ≠ 0.40

Solutions

Expert Solution

## Q ) National data indicates that​ 35% of households own a desktop computer. In a random

sample of 570​ households, 40% owned a desktop computer. Does this provide enough

evidence to show a difference in the proportion of households that own a​ desktop?

Identify the appropriate null and alternative hypotheses.

Answer : Here p = 35 % = 0.35 ( Population proportion )

n = sample size is 570 and

40% owned a desktop computer ie p_hat = 0.40 ( sample proportion )

Claim : Does this provide enough evidence to show a difference in the proportion of households that own a​ desktop?

A. H0: p= 0.35 Ha​: p ≠ 0.35

Correct option is A

orchestra answered 1 year ago
Next > < Previous

Related Solutions

Description: The data are from a national sample of 6000 households with a male head earning...
Description: The data are from a national sample of 6000 households with a male head earning less than $15,000 annually in 1966. The data were classified into 39 demographic groups for analysis. The study was undertaken in the context of proposals for a guaranteed annual wage (negative income tax). At issue was the response of labor supply (average hours) to increasing hourly wages. The study was undertaken to estimate this response from available data Approach: Our plan is to divide...
Description: The data are from a national sample of 6000 households with a male head earning...
Description: The data are from a national sample of 6000 households with a male head earning less than $15,000 annually in 1966. The data were classified into 39 demographic groups for analysis. The study was undertaken in the context of proposals for a guaranteed annual wage (negative income tax). At issue was the response of labor supply (average hours) to increasing hourly wages. The study was undertaken to estimate this response from available data SOLVE: Use SAS software to answer...
A random sample of 100 households and collect data on each household’s income. You find a...
A random sample of 100 households and collect data on each household’s income. You find a sample income standard deviation of $160,000. You want to test the null hypothesis that the population mean income is $100,000, using a p-value of 0.05, against the alternative that it does not equal $100,000. You will: A. Reject the null hypothesis if the sample mean is $130,000 B. Fail to reject the null hypothesis if the sample mean is between $80,000 and $120,000 C....
Below are the data on wages of a random sample of the First National Bank black...
Below are the data on wages of a random sample of the First National Bank black female hourly workers (in dollars per year): 16,015 17,516  17,27416,55520,788 19,312 17,124 18,405 19,090 12,641 17,813 18,206 19,338 15,953 16,904 Find a 90% confidence interval for the mean earnings of all black female hourly workers at First National Bank. Assume that population standard deviation is $1900.
A survey shows that 81% of households in the United States own a computer. You randomly...
A survey shows that 81% of households in the United States own a computer. You randomly select 12 households and ask if they own a computer. Answer the following questions. 1) Identify n 2) Identify p 3) Calculate 1 - p 4) Find the probability that exactly 6 of them respond yes 5) Find the probability that at least 6 of them respond yes 6) Find the probability that fewer than 6 of them respond yes 7) Find the probability...
A random sample data is given below for annual income from 30 households. 96727 96621 107235...
A random sample data is given below for annual income from 30 households. 96727 96621 107235 95366 97681 101890 95432 96697 107511 96886 96522 95385 97469 96664 106627 95744 95208 107795 98717 106622 107338 94929 95801 105601 97912 97611 96362 96244 97835 99610 A. From the info given above, what is the IQR? B. From the data above, construct a 95% confidence interval for the population's mean annual income. _____________< u > _____________ C. What is the statistical interpretation of...
In a simple random sample of 100 households, the sample mean number of personal computers was...
In a simple random sample of 100 households, the sample mean number of personal computers was 1.32. Assume the population standard deviation is 0.41. Construct a 95% confidence interval for the mean number of personal computers. (a) (1.24, 1.40) (b) (1.25, 1.39) (c) (0.15, 0.67) (d) (0.19, 0.63)
The type of household for the U.S. population and for a random sample of 411 households...
The type of household for the U.S. population and for a random sample of 411 households from a community in Montana are shown below. Type of Household Percent of U.S. Households Observed Number of Households in the Community Married with children 26%         105             Married, no children 29%         120             Single parent 9%         29             One person 25%         88             Other (e.g., roommates, siblings) 11%         69             Use a 5% level of significance to test the claim that the distribution of U.S. households fits the...
The type of household for the U.S. population and for a random sample of 411 households...
The type of household for the U.S. population and for a random sample of 411 households from a community in Montana are shown below. Type of Household Percent of U.S. Households Observed Number of Households in the Community Married with children 26%         105             Married, no children 29%         120             Single parent 9%         29             One person 25%         88             Other (e.g., roommates, siblings) 11%         69             Use a 5% level of significance to test the claim that the distribution of U.S. households fits the...
The type of household for the U.S. population and for a random sample of 411 households...
The type of household for the U.S. population and for a random sample of 411 households from a community in Montana are shown below. Type of Household Percent of U.S. Households Observed Number of Households in the Community Married with children 26%         101             Married, no children 29%         110             Single parent 9%         35             One person 25%         93             Other (e.g., roommates, siblings) 11%         72             Use a 5% level of significance to test the claim that the distribution of U.S. households fits the...
ADVERTISEMENT
Subjects
ADVERTISEMENT
Latest Questions
ADVERTISEMENT