Question

In: Statistics and Probability

A survey shows that 81% of households in the United States own a computer. You randomly...

A survey shows that 81% of households in the United States own a computer. You randomly select 12 households and ask if they own a computer. Answer the following questions. 1) Identify n 2) Identify p 3) Calculate 1 - p 4) Find the probability that exactly 6 of them respond yes 5) Find the probability that at least 6 of them respond yes 6) Find the probability that fewer than 6 of them respond yes 7) Find the probability that between 5 and 10 of them (inclusive) respond yes 8) Find the probability that no more than 8 of them respond yes 9) Find the probability that more than 9 of them respond yes 10) What is the expected (mean) number of “yes” response? 11) What is the standard deviation of the expected (mean) number of “yes” response?

Solutions

Expert Solution

1) Identify n

12

2) Identify p

81%

3) Calculate 1 - p

1-81% = 19%

To answer the following question, let us first describe the distribution of X, where X is the number of people who own a computer.

X ~ Binomial(12,0.81) with the following probability distribution:

X P(X=x)
0 0.000000002
1 0.000000113
2 0.000002655
3 0.000037728
4 0.000361888
5 0.002468457
6 0.012277323
7 0.044863001
8 0.119536285
9 0.226489803
10 0.289668537
11 0.224527766
12 0.079766443

4) Find the probability that exactly 6 of them respond yes

P(X=6) = 0.01227732324

5) Find the probability that at least 6 of them respond yes

P(X>=6) = 0.997129157522091

6) Find the probability that fewer than 6 of them respond yes 7)

P(X<6) = 1 -0.997129157522091 = 0.00287084247790914

Find the probability that between 5 and 10 of them (inclusive) respond yes

P(5<=X<=10) = 0.695303405271898

8) Find the probability that no more than 8 of them respond yes

P(X<=8) = 0.179547451227308

9) Find the probability that more than 9 of them respond yes

P(X>9) = 0.593962746002227

10) What is the expected (mean) number of “yes” response?

E(X) = n * p = 12 * 0.81 = 9.72

11) What is the standard deviation of the expected (mean) number of “yes” response?

SD(X) = (n * p * (1-p))0.5 = (1.8468)0.5 = 1.35897019834874

Please let me know in comments if anything is unclear. Will reply ASAP. Please upvote if satisfied!


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