how many atoms in the 60.0g of Agcl?

Expert Solution

How many atoms in the 60.0g of Agcl?

molar mass of AgCl = 143.37 g/mol

moles of AgCl = mass of AgCl/molar mass of AgCl

= 60.0/143.37

= 0.4185 moles.

1 mole of AgCl contains ---------> 2*6.023*10^23

0.4185 moles of AgCl contains -------> (0.4185*2*6.023*10^23)/1

= 5.041*10^23 atoms.

queen_honey_blossom answered 2 years ago

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