In: Statistics and Probability
The average modulus of rupture (MOR) for a particular grade of pencil lead is known to be 6500 psi with a standard deviation of 250 psi.
a) Find the probability that a random sample of 16 pencil leads with have an average MOR between 6400 and 6550 psi.
Solution :
Given that,
mean = = 6500
standard deviation = = 250
n = 16
= = 6500
= / n = 250 / 16 = 62.5
P(6400< < 6550)
= P[(6400 -6500) /62.5 < ( - ) / < (6550 -6500) /62.5 )]
= P(-1.60 < Z < 0.80)
= P(Z < 0.80 ) - P(Z < -1.60 )
Using standard normal table
= 0.7881 - 0.0548 = 0.7333
Probability = 0.7333