In: Statistics and Probability
Suppose x has a normal distribution with mean
μ = 36 and standard deviation σ = 5.
Describe the distribution of x values for sample size
n = 4. (Round σx to two
decimal places.)
μx | = |
σx | = |
Describe the distribution of x values for sample size
n = 16. (Round σx to two
decimal places.)
μx | = |
σx | = |
Describe the distribution of x values for sample size
n = 100. (Round σx to two
decimal places.)
μx | = |
σx | = |
Solution :
Given that,
mean = = 36
standard deviation = = 5
a) n = 4
= = 36
= / n = 5 / 4 = 2.5
mean = = 36
standard deviation = = 5
b) n = 16
= = 36
= / n = 5 / 16 = 1.25
mean = = 36
standard deviation = = 5
c) n = 100
= = 36
= / n = 5 / 100 = 0.5