In: Statistics and Probability
Age | Years |
---|---|
0 | 75.8 |
15 | 61.5 |
35 | 41.7 |
65 | 16.0 |
75 | 10.6 |
-Find the linear correlation coefficient. (Enter a number. Round your answer to four decimal places.)
R=
Speed (mph) | 0.0 | 0.5 | 1.0 | 1.5 | 2.0 | 2.5 | 3.0 | 3.5 | 4.0 |
---|---|---|---|---|---|---|---|---|---|
Pulse (bpm) | 61 | 66 | 69 | 75 | 76 | 81 | 85 | 91 | 94 |
-Find the least-squares regression for these data where speed is the independent variable, x, and pulse rate in beats per minute (bpm) is the dependent variable. (Enter a mathematical expression. Round your numerical answers to two decimal places.)
ŷ =
-Assuming the regression line is accurate for higher speeds, what is the expected pulse rate (in bpm) for someone traveling 5 mph? Round to the nearest whole number. (Enter a number.)
X Values
∑ = 190
Mean = 38
∑(X - Mx)2 = SSx = 4080
Y Values
∑ = 205.6
Mean = 41.12
∑(Y - My)2 = SSy = 3180.868
X and Y Combined
N = 5
∑(X - Mx)(Y - My) = -3595.8
R Calculation
r = ∑((X - My)(Y - Mx)) / √((SSx)(SSy))
r = -3595.8 / √((4080)(3180.868)) = -0.9981
Sum of X = 18
Sum of Y = 698
Mean X = 2
Mean Y = 77.5556
Sum of squares (SSX) = 15
Sum of products (SP) = 122.5
Regression Equation = ŷ = bX + a
b = SP/SSX = 122.5/15 = 8.17
a = MY - bMX = 77.56 - (8.17*2) = 61.22
ŷ = 8.17X + 61.22
For x=5, ŷ = (8.17*5) + 61.22=102.07=102