Question

C Code! I need all of the \*TODO*\ sections of this code completed.

For this dictionary.c program, you should end up with a simple English-French and French-English dictionary with a couple of about 350 words(I've provided 5 of each don't worry about this part). I just need a way to look up a word in a sorted array. You simply need to find a way to identify at which index i a certain word appears in an array of words and print out the corresponding French word, at the same index i.

#include <stdio.h>
#include <string.h>

const int NUMBER_ENTRIES = 352;

const char* english_NUMBER_ENTRIES[5]= {"war","size", "her","song","time"};

const char* french_NUMBER_ENTRIES[5] = {"guerre","taille","sa", "chanson","temps"};


int main(int argc, char **argv) 
{
  const int BUFFER_LENGTH = 128;
  char c, t;
  char user_word[BUFFER_LENGTH];
  enum { ENGLISH_FRENCH, FRENCH_ENGLISH } direction;
  int i;
  /* TODO: Add additional declarations here */
           printf("Dictionary\n\n");
  printf("English-French Dictionary\n\n");
  do {
    printf("Enter e for English-French\n");
    printf("Enter f for French-English\n");
    scanf("%c", &c);
    scanf("%c", &t);
  } while (!((c == 'e') || (c == 'f')));

  switch (c) {
  case 'e':
    direction = ENGLISH_FRENCH;
    break;
  case 'f':
    direction = FRENCH_ENGLISH;
    break;
  }

  printf("Please enter a word in ");
  switch (direction) {
  case ENGLISH_FRENCH:
    printf("English");
    break;
  case FRENCH_ENGLISH:
    printf("French");
    break;
  }
  printf(": ");
  i = 0;
  scanf("%c", &c);
  while (c != '\n') {
    user_word[i] = c;
    i++;
    if (i >= BUFFER_LENGTH) {
      i = BUFFER_LENGTH-1;
    }
    scanf("%c", &c);
  }
  user_word[i] = '\0';

  switch (direction) {
  case ENGLISH_FRENCH:
   printf(" The corresponding word is: ");
    /* TODO */
    break;
  case FRENCH_ENGLISH:
  printf(" The corresponding word is: ");
    /* TODO */
    break;
  }

  return 0;
}

Answer 1

Code :

#include <stdio.h>

#include <string.h>

const int NUMBER_ENTRIES = 352;

const char* english_NUMBER_ENTRIES[5]= {"war","size", "her","song","time"};

const char* french_NUMBER_ENTRIES[5] = {"guerre","taille","sa", "chanson","temps"};

int main(int argc, char **argv)

{

  const int BUFFER_LENGTH = 128;

  char c, t;

  char user_word[BUFFER_LENGTH];

  enum { ENGLISH_FRENCH, FRENCH_ENGLISH } direction;

  int i;

  /* TODO: Add additional declarations here */

           printf("Dictionary\n\n");

  printf("English-French Dictionary\n\n");

  do {

    printf("Enter e for English-French\n");

    printf("Enter f for French-English\n");

    scanf("%c", &c);

    scanf("%c", &t);

  } while (!((c == 'e') || (c == 'f')));

  switch (c) {

  case 'e':

    direction = ENGLISH_FRENCH;

    break;

  case 'f':

    direction = FRENCH_ENGLISH;

    break;

  }

  printf("Please enter a word in ");

  switch (direction) {

  case ENGLISH_FRENCH:

    printf("English");

    break;

  case FRENCH_ENGLISH:

    printf("French");

    break;

  }

  printf(": ");

  i = 0;

  scanf("%c", &c);

  while (c != '\n') {

    user_word[i] = c;

    i++;

    if (i >= BUFFER_LENGTH) {

      i = BUFFER_LENGTH-1;

    }

    scanf("%c", &c);

  }

  user_word[i] = '\0';

  int size = sizeof(english_NUMBER_ENTRIES)/sizeof(english_NUMBER_ENTRIES[0]);

  int index;

  switch (direction) {

  case ENGLISH_FRENCH:

   for(int i = 0; i<size; i++)

   {

       if(strcmp(english_NUMBER_ENTRIES[i], user_word) == 0) // strcmp is 0 if values are same

       {

           index = i; // get the index

       }

   }

    printf(" The corresponding word is: ");

    printf("%s\n", french_NUMBER_ENTRIES[index]);

    

    break;

  case FRENCH_ENGLISH:

    for(int i = 0; i<size; i++)

    {

        if(strcmp(french_NUMBER_ENTRIES[i], user_word) == 0) // strcmp is 0 if values are same

        {

            index = i; // get the index

        }

    }

    printf(" The corresponding word is: ");

    printf("%s\n",english_NUMBER_ENTRIES[index]);

    break;

  }

  return 0;

}

Variation in your code that i have done is :

OUTPUT :