In: Statistics and Probability
A sample of size 47 will be drawn from a population with mean 19 and standard deviation 14. Find the probability that will be greater than 22.
Solution :
Given that ,
mean = = 19
standard deviation = = 14
= / n = 14 / 47 = 2.0421
P( > 22) = 1 - P( < 22)
= 1 - P[( - ) / < (22 - 19) / 2.0421]
= 1 - P(z < 1.47)
= 1 - 0.9292
= 0.0708
Probability = 0.0708