In: Chemistry
Calculate [H30] for the following solutions. a) 6.16 x 10 ^-3 M HBr b) 1.80 x 10^-2 M KOH
(a) Given concentration of HBr = 6.16x10-3 M
HBr+ H2O H3O+ + Br-
1 mole of HBr produces 1 mole of H3O+
So [H3O+] = [HBr] = 6.16x10-3 M
(b) Given concentration of KOH = 1.80x10-2M
KOH K+ + OH-
1 mole of KOH produces 1 mole of OH-
So [OH-] = [KOH] = 1.80x10-2M
We know that [H3O+][OH-] = 1.0x10-14 M
[H3O+] = (1.0x10-14 ) / [OH-]
= (1.0x10-14 ) / (1.80x10-2)
= 5.55x10-13 M