Question
In: Chemistry
Calculate the pH of each of the following solutions: a. 0.00184M H+ b. 6.23 x 10-4M...
Calculate the pH of each of the following solutions:
a. 0.00184M H+
b. 6.23 x 10-4M HCl
c. 3.18 x 10-2M NaOH
d. 4.12 x 10-4M NaOH
Solutions
queen_honey_blossom answered 1 year agoRelated Solutions
1) Calculate of pH of each of the following strong acid solutions: (a) 8.5 x 10^-3...
1) Calculate of pH of each of the following strong acid
solutions: (a) 8.5 x 10^-3 M HBr, (b) 1.52 g of HNO3 in 575 mL of
solution, (c) 5.00 mL of 0.250 M HClO4 diluted to 50.0 mL, (d) a
solution formed by mixing 10.0 mL of 0.100 M HBr with 20.0 mL of
0.200 M HCl.
2) Calculate [OH-] and pH for (a) 1.5 x 10^-3 M Sr(OH)2, (b)
2.250 g of LiOH in 250.0 mL of solution,...
calculate the [H+] and the pH of each of the solutions. {Show calculation for a, c,...
calculate the [H+] and the pH of each of the
solutions. {Show calculation for a, c, d, e, h, j, and k.}
a) 0.358 M HNO3 pH =
:[H+]
=
e) 0.358 M HF pH =
:[H+]
=
i) 0.358 M HC6H5O pH =
:[H+]
=
b) 55.5 M H2O pH =
:[H+]
=
f) 0.358 M HNO2 pH =
:[H+]
=
j) 0.358 M Ba(OH)2 pH =
:[H+]
=
c) 0.358 M NaOH pH =
:[H+]
=
g) 0.358 M
CH3NH2 pH =...
Calculate the pH of the final equilibrium mixture in each of the following solutions: 1. 10...
Calculate the pH of the final equilibrium mixture in each of the
following solutions:
1. 10 mL of 0.005 M HNO3 are mixed with 5 mL of 0.006
M NaOH [answer: pH=2.87]
2. One mole of HCl is mixed with one mole of ammonia
(NH3; kb=1.76*10-5) to form one
liter aqueous solution. [answer: pH=4.62]
3. 0.5 moles of HCl is mixed with one mole of ammonia
(NH3; kb=1.76*10-5) to form one
liter aqueous solution. [answer: pH=9.24]
4. One mole of...
Calculate the pH of each of the following solutions: a) 0.05M HCl b) 1.00M NaOH c)...
Calculate the pH of each of the following solutions:
a) 0.05M HCl
b) 1.00M NaOH
c) 1.8x10-7M HNO3
Determine the pH of the following solutions (may need Ka and Kb
values):
d) 0.095M Hypochlorous acid
e) 0.0085M hydrazine
f) 0.165M hydroxylamine
Calculate analytical concentration for each of the following solutions: a) HCl solution, pH = 1.34 b)...
Calculate analytical concentration for each of the following
solutions:
a) HCl solution, pH = 1.34
b) Acetic acid solution, pH = 4.31
c) Sulfuric acid solution, pH = 2.21
d) Potassium hydroxide solution, pH = 12.21
Acetic acid: pKa = 4.76
Sulfuric acid: pKa,1 = strong, pKa,2 = 1.99
In water, [H3O+][OH–] = 1.00 ! 10–14
Ignore the effect of ionic strength.
Determine the pH of each of the following solutions A)8.1×10−3 M phenol B)9.5×10−2 M hydroxylamine. Calculate...
Determine the pH of each of the following solutions
A)8.1×10−3 M phenol
B)9.5×10−2 M hydroxylamine.
Calculate the percent ionization of propionic acid (C2H5COOH) in
solutions of each of the following concentrations
(Ka is given in Appendix D in the textbook).
A)0.260 M .
B) 8.05×10−2 M .
c)1.99×10−2 M .
A Tank with a dimension of length (L) x width (B) x height (H) of 4m...
A Tank with a dimension of length (L) x width (B) x
height (H) of 4m x 2m x 2m is filled with 1m depth of water and
with oil to the fullest. Density of oil ρm= 801 kg/m3. The tank is
open.
1.Calculate and draw pressure distribution on tank wall
2.Calculate force on the length and width side of tank wall, also
on the bottom of the tank Given: ρwater= 1000 kg/m3 , g = 9,81
m/sec2
Calculate the pH of each of the solutions and the change in pH to 0.01 pH...
Calculate the pH of each of the solutions and the change in pH
to 0.01 pH units caused by adding 10.0 mL of 2.81-M HCl to 340. mL
of each of the following solutions. Change is defined as final
minus initial, so if the pH drops upon mixing the change is
negative.
a) water pH before mixing = Correct: Your answer is correct.
pH after mixing= Incorrect: Your answer is incorrect.
pH change = Incorrect: Your answer is incorrect.
b)...
Calculate the pH of each of the solutions and the change in pH to 0.01 pH...
Calculate the pH of each of the solutions and the change in pH
to 0.01 pH units caused by adding 10.0 mL of 2.64-M HCl to 690. mL
of each of the following solutions. Change is defined as final
minus initial, so if the pH drops upon mixing the change is
negative.
a) water pH before mixing =
pH after mixing=
pH change =
b) 0.152 M C2H3O21-
pH before mixing =
pH after mixing=
pH change =
c) 0.152...
Calculate the pH of each of the solutions and the change in pH to 0.01 pH...
Calculate the pH of each of the solutions and the change in pH
to 0.01 pH units caused by adding 10.0 mL of 3.01-M HCl to 630. mL
of each of the following solutions.
Change is defined as final minus initial, so if the pH drops
upon mixing the change is negative.
a) water
pH before mixing =
pH after mixing=
pH change =
b) 0.109 M
C2H3O21-
pH before mixing =
pH after mixing=
pH change =
c) 0.109...
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