Calculate [H3O+] in the following solutions. a)3.0×10−2 M HCl and 7.0×10−2 M HOCl b)0.105 M NaNO2...

Calculate [H3O+] in the following solutions.

a)3.0×10−2 M HCl and 7.0×10−2 M HOCl

b)0.105 M NaNO2 and 5.50×10−2 M HNO2

c)5.30×10−2 M HCl and 7.64×10−2 M NaC2H3O2

Solutions

Expert Solution

concentration of [H3O+] = 3.0 x 10^-2 M

pH = pKa + log [NaNO2 / HNO2]

= 3.25 + log [0.105 / 5.50×10⁻²]

= 3.53

[H3O+] = 10^-3.53

[H3O+] = 3.0 x 10^-4 M

3) 5.35×10⁻² M HCl and 7.66×10⁻² M NaC2H3O2

C2H3O2- + HCl ---------------> CH3COOH + Cl -

7.64×10⁻² 5.30×10⁻² 0

2.34 x 10^-2 0 5.30×10⁻²

pH = pKa + log [2.34 x 10^-2 / 5.30×10⁻²]

= 4.74 + log [2.34 x 10^-2 / 5.30×10⁻²]

= 4.38

[H3O+] = 4.2 x 10^-5 M

queen_honey_blossom answered 1 year ago

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