Question

(a) What is the magnitude of the angular momentum for an ? = 30 electron?
? J

Answer 1

given the atoms has 30 electrons

Since the number of electons is equal to the atomic number her Z=30

writing the electronic configuration we get

1s2

2s2

2p6

3s2

3p6

3d10

4s2

herefore the last (outermost) electrons of Zn are located in 4s orbital.

Now, the quantum numbers:

( Principal quantum number) describes the shell of the electron.
n = 4
(Azimuthal quantum number or Angular momentum quantum number) describes the subshell of the electron. Since we specify the e- in s-subshell,
l = 0
(Magnetic quantum number) describes the type of the orbital of the electron. The e- is in s orbital, therefore,
m = 1
(Spin quantum number) Each orbital can hold maximum 2 e- with opposite spins. These are represented as +1/2 and -1/2.
Since, Zn has 2e- in its outermost shell, one of them will have
s = +1/2 and the other s = -1/2.

What is the magnitude of the angular momentum