In: Statistics and Probability
A savvy business owner wanted to assess whether the type of fragrance influenced the amount of money spent. He tried peppermint, lavender, male cologne, and a floral perfume in his four stores. Amount of money spent (in hundreds) is reported for each type of fragrance. Conduct a one-way repeated measures ANOVA to determine whether fragrance influences total amount of money spent.
| 
 Peppermint  | 
 Lavender  | 
 Cologne  | 
 Floral  | 
| 
 4.2  | 
 3.3  | 
 5.1  | 
 3.9  | 
| 
 5.1  | 
 1.8  | 
 4.9  | 
 4.3  | 
| 
 4.8  | 
 3.0  | 
 3.2  | 
 3.5  | 
| 
 6.2  | 
 3.2  | 
 4.0  | 
 3.7  | 
| 
 3.1  | 
 2.3  | 
 3.8  | 
 2.1  | 
| 
 4.5  | 
 2.9  | 
 4.7  | 
 2.3  | 
| 
 4.8  | 
 3.5  | 
 3.8  | 
 1.0  | 
| 
 3.7  | 
 4.7  | 
 4.1  | 
 2.8  | 
| 
 2.8  | 
 3.1  | 
 3.5  | 
 4.2  | 

Go To data tab in excel choose data analysis and choose Anova: Two-Factor Without Replication.

Rows refers to test scores for each of the flavours. Notice that the p-value or probability of obtaining an F statistic of 2.355 or larger when the null hypothesis is true is 0.478. Since the p-value is larger than the specified alpha of 0.05, the null hypothesis is not rejected; there is a no significant statistical difference between the means of each fragrance influences total amount of money spent.
Columns refers to the four categories of test amount: mathematics, reading, science and social studies. The p-value in cell M24 is very close to 0. This means that the probability of obtaining an F statistic of 3.01 or larger when the null hypothesis is true is also very close to 0. Since the p-value is less than the specified alpha of 0.05 and the calculated F statistic is larger than the value for F crit, the null hypothesis is rejected. There is a significant statistical difference in the calculated means of the four categories.