Question

In: Statistics and Probability

A savvy business owner wanted to assess whether the type of fragrance influenced the amount of...

A savvy business owner wanted to assess whether the type of fragrance influenced the amount of money spent. He tried peppermint, lavender, male cologne, and a floral perfume in his four stores. Amount of money spent (in hundreds) is reported for each type of fragrance. Conduct a one-way repeated measures ANOVA to determine whether fragrance influences total amount of money spent.

Peppermint

Lavender

Cologne

Floral

4.2

3.3

5.1

3.9

5.1

1.8

4.9

4.3

4.8

3.0

3.2

3.5

6.2

3.2

4.0

3.7

3.1

2.3

3.8

2.1

4.5

2.9

4.7

2.3

4.8

3.5

3.8

1.0

3.7

4.7

4.1

2.8

2.8

3.1

3.5

4.2

Solutions

Expert Solution

Go To data tab in excel choose data analysis and choose Anova: Two-Factor Without Replication.

Rows refers to test scores for each of the flavours. Notice that the p-value or probability of obtaining an F statistic of 2.355 or larger when the null hypothesis is true is 0.478. Since the p-value is larger than the specified alpha of 0.05, the null hypothesis is not rejected; there is a no significant statistical difference between the means of each fragrance influences total amount of money spent.

Columns refers to the four categories of test amount: mathematics, reading, science and social studies. The p-value in cell M24 is very close to 0. This means that the probability of obtaining an F statistic of 3.01 or larger when the null hypothesis is true is also very close to 0. Since the p-value is less than the specified alpha of 0.05 and the calculated F statistic is larger than the value for F crit, the null hypothesis is rejected. There is a significant statistical difference in the calculated means of the four categories.  


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