In: Statistics and Probability
Q1. A local sports bar wanted to determine whether Ohio
University students prefer a particular type of food in their
establishment. A sample of students responses are reproduced below.
Do students prefer a particular type of bar food? Use critical
value = 6.58.
Use the numbers below for this question
only!
Nachos Pizza Chicken
Wings Cheese
Sticks
33 34 46 46
What would the expected value for Cheese Sticks
be?
Q2. A local sports bar wanted to determine whether Ohio
University students prefer a particular type of food in their
establishment. A sample of students responses are reproduced below.
Do students prefer a particular type of bar food? Use critical
value = 6.58.
Use the numbers below for this question
only!
Nachos Pizza Chicken
Wings Cheese
Sticks
44 40 42 43
What is the calculated chi-squared value?
Q.3 Using a critical value of 6.58, was there a significant preference for what students eat in a sports bar based on the obtained chi-square value in Question 2?
Yes
No
Q1:
Category | Observed Frequency (O) | Proportion, p | Expected Frequency (E) |
Nachos | 33 | 0.25 | 159 * 0.25 = 39.75 |
Pizza | 34 | 0.25 | 159 * 0.25 = 39.75 |
Chicken | 46 | 0.25 | 159 * 0.25 = 39.75 |
Cheese sticks | 46 | 0.25 | 159 * 0.25 = 39.75 |
Total | 159 | 1.00 | 159 |
Expected value for Cheese Sticks = 39.75
-------------
Q2:
Category | Observed Frequency (O) | Proportion, p | Expected Frequency (E) | (O-E)²/E |
Nachos | 44 | 0.25 | 169 * 0.25 = 42.25 | (44 - 42.25)/42.25 = 0.0725 |
Pizza | 40 | 0.25 | 169 * 0.25 = 42.25 | (40 - 42.25)/42.25 = 0.1198 |
Chicken | 42 | 0.25 | 169 * 0.25 = 42.25 | (42 - 42.25)/42.25 = 0.0015 |
Cheese sticks | 43 | 0.25 | 169 * 0.25 = 42.25 | (43 - 42.25)/42.25 = 0.0133 |
Total | 169 | 1.00 | 169 | 0.2071 |
Test statistic:
Chi-squared value, χ² = ∑ ((O-E)²/E) = 0.2071
Q3:
χ² = 0.2071 < 6.58, Do not reject the null hypothesis.
No, there is no significant preference for what students eat in a sports bar based on the obtained chi-square.