Question

Draw the VSEPR picture for (1) CO2, (2) CH2O, (3) CH4, (4). C2H6, and Identify the,

(A) electron pair geometry, (B) the molecular geometry and (C). the bond angles.

Answer 1

1) CO2:

O=C=O

central atom = C, bonded atoms = 2, lone pairs = 0

a) electron pair geometry for AB2E0 = this must be LINEAR

b) molecular geoemtry, since no lone pairs, this is also LINEAR

c) bond angle is 180

Q2)

CH2O

Central atom = C, bonded atoms = 3, lone pairs = 0

Then,

a) electron pair geometry = trigonal planar

b) molecular geometry = trigonal planar, since no lone pairs present

c) bond angle must be 120 º

Q3.

this is methane, CH4

central atom = C

bonded atoms = 4, lone pairs = 0

a) electron geometry for AB4 is tetrahedral

b) molecular geometry is tetrahedral as well

c) angle is about 104 approx.

Q4.

Note that C2H6 is not ABxEy type

We can only analyse both central atoms ( left Carbon and rigt Carbon )

since it is the same case:

a) electron pair geometry for left C = tetrahedral, same for right carbon

b) molecular goeemtry for both carbons is, once again, tetrahedral for both

c) angle is always 109º