In: Statistics and Probability
An experiment has been conducted for four treatments with eight blocks. Complete the following analysis of variance table (to 2 decimals, if necessary and p-value to 4 decimals). If your answer is zero enter "0".
Source of Variation | Sum of Squares | Degrees of Freedom | Mean Square | F | p-value | |
Treatments | 700 | |||||
Blocks | 600 | |||||
Error | ||||||
Total | 1,600 |
Use = .05 to test for any significant differences.
Here we have 4 treatments, so a = 4, and 8 blocks, so b= 8 , so N = 8*4
So treatment df = a -1 = 4-1 =3 , blocks df = b-1 = 8-1 = 7
Error df = ( a -1 ) ( b-1) = 3*7 = 21 , Total df = N-1 = 32 - 1 = 31
Total sum of square = Treatment sum of square + Blocks sum of squares + Error sum of square
1600 = 700 + 600 + Error sum of square
So Error sum of square = 1600 - 700 - 600 = 300
Source of variation | Sum of square | Degrees of freedom | Mean Square | F | P value |
Treatment | 700 | 3 | 233.33 | 16.33 | 0 |
Blocks | 600 | 7 | 85.71 | 6 | 0.0006 |
Error | 300 | 21 | 14.29 | ||
Total | 1600 | 31 |
Using excel formula, p value is given by,
P value for treatment = " =f.dist.rt(16.33,3,21)" = 0.0000
So here p value < ( 0.05) . Hence we reject null hypothesis.
Conclusion : Treatments are significant.
P value for Blocks = " =f.dist.rt(6,7,21)" = 0.0006
So here p value < ( 0.05) . Hence we reject null hypothesis.
Conclusion : Blocks are significant.