50 L of a gas were collected over water when the barometer read 684.0 mmHg and...

50 L of a gas were collected over water when the barometer read 684.0 mmHg and the temperature was 14 oC . What volume would the dry gas occupy at standard conditions?

HINT: Consider Dalton’s law of partial pressures.

Expert Solution

PT = 648mmHg

PH2O = 12mmHg ( water vapor pressure at 14⁰C)

Pgas = PT-PH2O

= 684-12 = 672mmHg

Given conditions STP conditions

V1 = 50L V2 =

T1 = 14+273 = 287K T2 = 273K

P1 = 672mmHg P2 = 760mmHg

P1V1/T1 = P2V2/T2

V2 = P1V1T2/T1P2

= 672*50*273/287*760 = 42L

The volume of gas = 42L

queen_honey_blossom answered 1 year ago

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