In: Statistics and Probability
The following data on price ($) and the overall score for 6
stereo headphones that were tested by Consumer Reports were as
follows.
| Brand | Price | Score | 
| Bose | 180 | 78 | 
| Scullcandy | 150 | 75 | 
| Koss | 95 | 68 | 
| Phillips/O'Neill | 70 | 56 | 
| Denon | 80 | 40 | 
| JVC | 35 | 26 | 
a. Does the t test indicate a significant relationship between price and the overall score?
The test t-Conclusion at α = .05
t = (to 2 decimal places.)
p-value is -
What is your conclusion? Use α = .05.
- Select your answer -There is a significant relationship between
price and overall scoreThere is no significant relationship between
price and overall scoreItem 3 .
b. Test for a significant relationship using
the F test.
p-value is - Select your answer -less than .01between .01
and .025between .025 and .05between .05 and .1greater than .1Item
4
What is your conclusion? Use α = .05.
Because p-value is - -greater than or equal toless than or equal toequal toItem 5 .05, we - Select your answer 6 H0: β1 is - Select your answer -greater than or equal to zeroless than or equal to zeroequal to zeroItem 7 .
c. Show the ANOVA table for these data. Round your answers to three decimal places, if necessary.
| Source of Variation  | 
Sum of Squares  | 
Degrees of Freedom  | 
Mean Square  | 
F  | 
p-value  | 
| Regression | |||||
| Error | |||||
| Total | 

| SST=Syy= | 2,136.8333 | |
| SSE =Syy-(Sxy)2/Sxx= | 467.660 | |
| SSR =(Sxy)2/Sxx = | 1,669.1734 | |
| s2 =SSE/(n-2)= | 116.9150 | |
| std error σ = | =se =√s2= | 10.8127 | 
a)
| test stat t = | (bo-β1)/se(β1)= | = | 3.78 | 
| p value: | = | 0.0195 ~0.019 or between 0.01 and 0.025 | 
There is a significant relationship between price and overall score
b)test statistic F =14.28
between .01 and .025
Because p-value is less than or equal to 0.05 we reject Ho :β1 is equal to zero
c)
| SS | df | MS | F | p value | 
| 1669.173 | 1 | 1669.173 | 14.277 | 0.019 | 
| 467.660 | 4 | 116.915 | ||
| 2136.833 | 5 |