In: Statistics and Probability
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 The following data on price ($) and the overall score for 6
stereo headphones that were tested by Consumer Reports
were as follows. 
 a. Does the t test indicate a significant relationship between price and the overall score? The test t-Conclusion at = .05 t = (to 2 decimal places.) p-value is - Select your answer -less than .01between .01 and .025between .025 and .05between .05 and .1greater than .1Item 2 What is your conclusion? Use = .05. b. Test for a significant relationship using
the F test. What is your conclusion? Use = .05. Because p-value is - Select your answer -greater than or equal to less than or equal to equal to Item 5 .05, we - Select your answer -accept reject Item 6 H 0: β 1 is - Select your answer -greater than or equal to zero less than or equal to zero equal to zero Item 7 . c. Show the ANOVA table for these data. Round your answers to three decimal places, if necessary. 
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| x | y | (x-x̅)² | (y-ȳ)² | (x-x̅)(y-ȳ) | 
| 186 | 78 | 6724.00 | 441.00 | 1722.00 | 
| 162 | 78 | 3364.00 | 441.00 | 1218.00 | 
| 90 | 60 | 196.00 | 9.00 | -42.00 | 
| 78 | 54 | 676.00 | 9.00 | 78.00 | 
| 72 | 42 | 1024.00 | 225.00 | 480.00 | 
| 36 | 30 | 4624.00 | 729.00 | 1836.00 | 
| ΣX | ΣY | Σ(x-x̅)² | Σ(y-ȳ)² | Σ(x-x̅)(y-ȳ) | |
| total sum | 624 | 342 | 16608 | 1854.000 | 5292.000 | 
| mean | 104.000 | 57.000 | SSxx | SSyy | SSxy | 
sample size ,   n =   6  
       
here, x̅ = Σx / n=   104.00   ,
    ȳ = Σy/n =   57.00  
          
       
SSxx =    Σ(x-x̅)² =    16608.0000  
       
SSxy=   Σ(x-x̅)(y-ȳ) =   5292.0  
       
          
       
estimated slope , ß1 = SSxy/SSxx =   5292.0  
/   16608.000   =   0.31864
          
       
intercept,   ß0 = y̅-ß1* x̄ =  
23.86127          
          
       
so, regression line is   Ŷ =  
23.86   +   0.3186   *x
          
       
SSE=   (SSxx * SSyy - SS²xy)/SSxx =   
167.7486          
          
       
std error ,Se =    √(SSE/(n-2)) =   
6.4759          
---------------
a)
Ho:   ß1=   0      
   
H1:   ß1╪   0      
   
n=   6          
   
alpha =   0.05      
       
estimated std error of slope =Se(ß1) = Se/√Sxx =   
6.476   /√   16608.00   =  
0.0503
          
       
t stat = estimated slope/std error =ß1 /Se(ß1) =
   0.3186   /   0.0503  
=   6.34
p-value is-less than .01
There is a significant relationship between price and overall score
b)
p-value is-less than .01
we -reject H 0: β 1 is greater than or equal to zero
c)
| Anova table | |||||
| variation | SS | df | MS | F-stat | p-value | 
| regression | 1686.251 | 1 | 1686.251 | 40.209 | less than 0.01 | 
| error, | 167.749 | 4 | 41.937 | ||
| total | 1854.000 | 5 |