In: Advanced Math
The temperature at some instant (t = 0) of a laterally insulated solid rod of 1 unit length is given by ?(?,?) = sin ?? for 0 x 1, where x is measured from left end of the rod to the other end on the right. Also, at time t = 0, the left end of the rod is subjected to 0oC and maintained over the time, while the right end is insulated when t > 0. Note that the term x in the expression of the temperature is in radian. The temperature variation in the rod,
?(?,?), satisfies the heat equation: ?? ?? = ?( 2 ?^2? /??^ 2 )
Solve the above heat equation numerically with del x = 0.2 and del t = 0.04 using explicit formula: ?(?? ,??+1) = ??(??−1,??) + (1 − 2?)?(?? ,??) + ??(??+1,??)
Given that, c ^2 = 0.1 and ? = ? ^2 Δ? (Δ?)2 .
Estimate the numerical values for ?(?,?) at t = 0.08, giving your answers at 4 decimal points
Given:
The temperature variation in rod satisfies the heat equation:
Initial Condition:
Left boundary condition:
Right boundary condition:
for all t > 0 as the right end is insulated.
x | 0 | 0.2 | 0.4 | 0.6 | 0.8 | 1.0 |
U | 0 | 0.5878 | 0.9511 | 0.9511 | 0.5878 | 0 |
Explicit formula:
Solution:
For x = 0.2 to 0.8:
For x = 1.0:
At t = 0.04:
For x = 0.2
For x = 0.4
For x = 0.6
For x = 0.8
For x = 1.0:
At t = 0.08:
For x = 0.2
For x = 0.4
For x = 0.6
For x = 0.8
For x = 1.0:
x | 0 | 0.2 | 0.4 | 0.6 | 0.8 | 1.0 |
t = 0 | 0 | 0.5878 | 0.9511 | 0.9511 | 0.5878 | 0 |
t = 0.04 | 0 | 0.5856 | 0.9475 | 0.9475 | 0.5856 | 0.5856 |
t = 0.08 | 0 | 0.5834 | 0.9439 | 0.9439 | 0.5892 | 0.5892 |