Find the unique solution u of the parabolic boundary value
problem
Ut −Uxx =e^(−t)*sin(3x), 0<x<π, t>0,
U(0,t) = U(π,t) = 0, t > 0,
U(x, 0) = e^(π), 0 ≤ x ≤ π.
Solve the following initial value problems:
a) ut+xux= -tu, x is in R, t>0; u(x,0) =f(x), x is in R.
c) ut+ux=-tu, x is in R, t>0; u(x,0)=f(x), x is in R
d)2ut+ux = -2u, x,t in R, t>0; u(x,t)=f(x,t) on the straight
line x = t, where f is a given function.
For the wave equation, utt = c2uxx, with the following boundary
and initial conditions,
u(x, 0) = 0
ut(x, 0) = 0.1x(π − x)
u(0,t) = u(π,t) = 0
(a) Solve the problem using the separation of variables.
(b) Solve the problem using D’Alembert’s solution. Hint: I would
suggest doing an odd expansion of ut(x,0) first; the final solution
should be exactly like the one in (a).