In: Chemistry
A gravimetric analysis of a mixture of gases used in a
manufacturing process has the following proportions: 52 % nitrogen
(N2), 27 % oxygen (O2), 11 % hydrogen (H2) and 10 % carbon dioxide
(CO2). The mixture of gases has a temperature of 300 K and pressure
of 350 kPa.
Determine the following:
(i) Mass fractions and molar masses for each of the mixture's
constituent gases.
(ii) Specific heat capacities at constant pressure for each of the constituent gases and the specific heat capacity at constant pressure for the mixture of gases.
(iii) Specific gas constants for each of the constituent gases, the specific gas constant for the mixture and the mean molar mass for the mixture of gases.
(iv) Volume fractions for each of the constituent gases.
(v) Specific volume, density, specific heat capacity at constant
volume and the ratio of specific heat capacities of the mixture of
gases.
(i) Molar mass of N2 =28 kg/mol
Molar mass of O2 =32 kg/mol
Molar mass of CO2 =44 kg/mol
Molar mass of H2 =2 kg/mol
Consider 100 kmol of mixture, then the mass of each component is,
N (O2)= 27 kmol => m(O2)=27*32= 864 kg
similarly for m(N2)=52*28= 1456 ; m(CO2)=10*44=440 ; m(H2)=2*11=22 kg
total mass= 864+1456+440+22=2782kg
then, mass fraction, mf(N2)=1456/2782= 52.34% ; mf(O2)= 864/2782= 31.05% ; mf(CO2)=440/2782= 15.81% ; mf(H2)=22/2782= 0.80%
(ii) Total mass = 2782/100 = 27.82 kg/mol
For specific heat capacity, for diatomic molecules, Cv=5/2*R and for triatomic Cv=7/2*R ;
Cp=Cv + R
Cv(N2) ; (H2) ; (O2)= 5/2*R=20.785 ; (CO2)= 29.099
Cp (N2) ; (H2) ; (O2) = Cv +R = 29.099 ; Cp (CO2)= Cv +R = 37.413
(iii) Specific gas constant = R/M= 8.314/27.82 = 0.299 kJ/Kg K
(iv)Volume fraction and mole fractions are same; mole fraction = no. of moles of each constituent / total number of moles