Question

In: Chemistry

A mixture of gases collected over water at 14oC has a total pressure of 1.198 atm...

A mixture of gases collected over water at 14oC has a total pressure of 1.198 atm and occupies 72 mL. How many grams of water escaped into the vapor phase?

Solutions

Expert Solution

The total pressure of gases over water at140 C, P = 1.198 atm

at 140 C the vapour pressure ofwater = 0.016atm

                 Total volume = 72.mL

                                     = 0.072 L

             Temperature   = (14 +273 ) K

                                      = 287 K

              Ideal gas equation PV = nRT

               so number of water moles , n = PV / RT

                                                              = ( 0.016 atm * 0.072L) / (0.08206 L.atm /mol.K*287K)

                                                              = 4.89 x 10-5 mol

                molar mass of water = 18 g / mol

          Therefore mass of water present in vapor state ,m = 18g /mol x 4.89 x 10-5 mol

                                                                                      = 8.80 x 10-4 g

                          8.80 x 10-4 g of water is escaps into vapor phase


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