Question
In: Chemistry
A mixture of gases collected over water at 14oC has a total pressure of 1.198 atm...
A mixture of gases collected over water at 14oC has a total pressure of 1.198 atm and occupies 72 mL. How many grams of water escaped into the vapor phase?
Solutions
Expert Solution
The total pressure of gases over water at140 C, P = 1.198 atm
at 140 C the vapour pressure ofwater = 0.016atm
Total volume = 72.mL
= 0.072 L
Temperature = (14 +273 ) K
= 287 K
Ideal gas equation PV = nRT
so number of water moles , n = PV / RT
= ( 0.016 atm * 0.072L) / (0.08206 L.atm /mol.K*287K)
= 4.89 x 10-5 mol
molar mass of water = 18 g / mol
Therefore mass of water present in vapor state ,m = 18g /mol x 4.89 x 10-5 mol
= 8.80 x 10-4 g
8.80 x 10-4 g of water is escaps into vapor phase
queen_honey_blossom answered 2 years agoRelated Solutions
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