1. What is the momentum (p) of a 960-MeV proton
(that is, its kinetic energy is 960 MeVMeV )?
Express your answer with the appropriate units.
2. An electron (mmm = 9.11×10−31 kg
) is accelerated from rest to speed vv by a conservative force. In
this process, its potential energy decreases by
6.70×10−14 JJ . Determine the electron's speed, v. (in
term of c.)
What is the energy of a photon whose momentum is the same as a
proton with the proton’s Kinetic energy being 100 MeV? What is the
velocity of the proton? If it enters a magnetic field of 2T what is
the radius of curvature of its path?
Calculate the speed (in m/s) of an electron and a proton with a
kinetic energy of 1.70 electron volt (eV). (The electron and proton
masses are me = 9.11 ✕ 10−31 kg and mp = 1.67 ✕ 10−27 kg.
Boltzmann's constant is kB = 1.38 ✕ 10−23 J/K.)
(a) an electron m/s
(b) a proton m/s
(c) Calculate the average translational kinetic energy in eV of
a 3.15 ✕ 102 K ideal gas particle. (Recall from Topic 10 that 1...
Antiproton of kinetic energy E_k collides (bumps) with a proton
at rest. How much energy is available for the production of new
particles that have a mass.
relativistic calculation is needed and a must!
A proton moves with a speed of 0.895c.
(a) Calculate its rest energy. _____MeV
(b) Calculate its total energy. ____GeV
(c) Calculate its kinetic energy._____GeV
A proton in a high-energy accelerator moves with a speed of
c/2. Use the work–kinetic energy theorem to find the work
required to increase its speed to the following speeds.
A. .710c answer in units of MeV?
b..936c answer in units of Gev?
A proton in a high-energy accelerator moves with a speed of
c/2. Use the work–kinetic energy theorem to find the work
required to increase its speed to the following speeds.
(a) 0.530c
MeV
(b) 0.940c
GeV
(a) Find the linear momentum and kinetic energy of a bullet of
mass 5.70 10-2 kg moving at a speed of 330
m/s.
linear momentum
=
kinetic energy
=
(b) Find the linear momentum and kinetic energy of a football
player of mass 111 kg moving at a speed of 10.0 m/s.
linear momentum
=
kinetic energy
=
(c) Find the linear momentum and kinetic energy of a truck of mass
1.00 104 kg moving at a speed of 20.5
m/s.
linear...
1. Show that the Kinetic Energy and the Momentum are conserved
in this system. (Remember that momentum is a vector, so you need to
show the conservation of the momentum in x and y directions
separately.)
Data:
Before the collision: m1= 1kg v1x
=1 m/s v1y=0 m/s m2=1kg v2x=-1m/s
v2y=0 m/s
After the collision: m1= 1kg v1x
=-0.778 m/s v1y=-0.629 m/s m2=1kg
v2x= 0.778 m/s v2y=0.629 m/s
2. From the data, calculate the direction(angles) of the final
velocities of the...