In: Statistics and Probability
A professor wishes to estimate the proportion of college students that have never cheated
during a course. She wishes to estimate the proportion to be within 4.15% with 96%
confidence. How many teenagers are needed for the sample?
A. 613
B. 611
C. 612
D. 614
E. Insufficient information to answer the question
Solution :
Given that,
=
0.5 ( assume )
1 -
= 1 - 0.5 = 0.5
margin of error = E = 4.15% = 0.0415
At 96% confidence level the z is ,
= 1 - 96% = 1 - 0.96 = 0.04
/ 2 =0.02
Z/2
= Z0.02= 2.05 ( Using z table )
Sample size = n = (Z/2
/ E)2 *
* (1 -
)
= (2.05 / 0.0415)2 * 0.5 * 0.5
= 611
Sample size =611