Calculate the mass of each sample. 13.5 mol HNO2 1.40 ×10−3mol H2O 69.4 mmol SO2 1.34...

Calculate the mass of each sample.

13.5 mol HNO2
1.40 ×10−3mol H2O
69.4 mmol SO2
1.34 mol xenon dioxide

Solutions

Expert Solution

Molar mass of HNO₂ = (1 x 1 + 1 x 14 + 2 x 16) = 47 g/mol

Thus, the mass of 1 mol HNO₂ = 47 g

Therefore the mass of 13.5 mol HNO₂ = 47 x 13.5 = 634.5 g

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Molar mass of H₂O = ( 2 x 1 + 1 x 16) = 18 g/mol

Thus the mass of 1 mol H₂O =18 g

Therefore the mass of 1.40 ×10⁻³ mol H₂O = 18 x 1.40 ×10⁻³ = 0.0252 g

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Atomic mass of sulfur = 32 g/mol

Molar mass of SO₂ = (1 x 32 + 2 x 16) = 64 g/mol

Thus the mass of 1 mol SO₂ = 64 g

Therefore the mass of 69.4 mmol or 69.4 x 10^-3 mol SO₂ = 64 x 69.4 x 10^-3 = 4.4416 g

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Atomic mass of xenon = 131.293 g/mol

Molar mass of XeO₂ = (1 x 131.293 + 2 x 16) = 163.293 g/mol

Thus the mass of 1 mol XeO₂ = 163.293 g

Therefore the mass of 1.34 mol XeO₂ = 163.293 x 1.34 = 218.81262 g

queen_honey_blossom answered 1 year ago

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