Question

In: Statistics and Probability

A manufacturer of chocolate chips would like to know whether its bag filling machine works correctly...

A manufacturer of chocolate chips would like to know whether its bag filling machine works correctly at the 403 gram setting. It is believed that the machine is underfilling the bags. A 38 bag sample had a mean of 400 grams. Assume the population standard deviation is known to be 11. Is there sufficient evidence at the 0.01 level that the bags are underfilled?

Step 1 of 6: State the null and alternative hypotheses.

Step 2 of 6: Find the value of the test statistic. Round your answer to two decimal places.

Step 3 of 6: Specify if the test is one-tailed or two-tailed.

Step 4 of 6: Find the P-value of the test statistic. Round your answer to four decimal places.

Step 5 of 6: Identify the level of significance for the hypothesis test.

Step 6 of 6: Make the decision to reject or fail to reject the null hypothesis.

Solutions

Expert Solution

Solution:

Step 1 :

The null and alternative hypotheses are as follows:

H​​​​​​0 : μ = 403 grams i.e. The population mean of the weights of the bags filled by bag filling machine is 403 grams.

H​​​​​​0 : μ < 403 grams i.e. The population mean of the weights of the bags filled by bag filling machine is less than 403 grams.

Step 2 :

To test hypothesis we shall use z-test for single mean. The test statistic is given as follows:

Where, x̄ is sample mean, μ is hypothesized value of population mean, σ is population standard deviation and n is sample size.

We have, x̄ = 400 grams, μ = 403 grams, σ = 11 grams and n = 38

On rounding to 2 decimal places we get, Z = -1.68.

The value of the test statistic is -1.68.

Step 3:

Our test is one-tailed (left-tailed) test.

Step 4 :

Since, our test is left-tailed test, therefore we shall obtain left-tailed p-value for the test statistic. The left-tailed p-value for the test statistic is given as follows:

p-value = P(Z < value of the test statistic)

p-value = P(Z < -1.6812)

p-value = 0.0464

Step 5 :

The level of significance for the hypothesis test is 0.01.

Step 6:

We make decision rule as follows:

If p-value is greater than the significance level, then we fail to reject the null hypothesis (H​​​​0) at given significance level.

If p-value is less than the significance level, then we reject the null hypothesis (H​​​​0) at given significance level

We have, p-value = 0.0464 and significance level = 0.01

(0.0464 > 0.01)

Since, p-value is greater than the significance level of 0.01, therefore we shall be fail to reject the null hypothesis (H​​​​​​0) at significance level of 0.01.

Conclusion: At significance level of 0.01, there is not enough evidence to support the claim that machine is underfilling the bags.

Please rate the answer. Thank you.


Related Solutions

A manufacturer of chocolate chips would like to know whether its bag filling machine works correctly...
A manufacturer of chocolate chips would like to know whether its bag filling machine works correctly at the 440 gram setting. It is believed that the machine is underfilling or overfilling the bags. A 21 bag sample had a mean of 443 grams with a standard deviation of 11. Assume the population is normally distributed. A level of significance of 0.01 will be used. Specify the type of hypothesis test. answer can be left tailed test,right tailed test or two...
A manufacturer of chocolate chips would like to know whether its bag filling machine works correctly...
A manufacturer of chocolate chips would like to know whether its bag filling machine works correctly at the 413.0 gram setting. It is believed that the machine is underfilling the bags. A 41 bag sample had a mean of 403.0 grams. A level of significance of 0.02 will be used. Determine the decision rule. Assume the variance is known to be 676.00.
A manufacturer of chocolate chips would like to know whether its bag filling machine works correctly...
A manufacturer of chocolate chips would like to know whether its bag filling machine works correctly at the 440 gram setting. It is believed that the machine is underfilling the bags. A 21 bag sample had a mean of 430 grams with a standard deviation of 29 . Assume the population is normally distributed. A level of significance of 0.02 will be used. Find the P-value of the test statistic. You may write the P-value as a range using interval...
A manufacturer of chocolate chips would like to know whether its bag filling machine works correctly...
A manufacturer of chocolate chips would like to know whether its bag filling machine works correctly at the 420 gram setting. It is believed that the machine is underfilling the bags. A 49 bag sample had a mean of 413 grams. Assume the population variance is known to be 676. A level of significance of 0.1 will be used. Find the P-value of the test statistic. You may write the P-value as a range using interval notation, or as a...
A manufacturer of chocolate chips would like to know whether its bag filling machine works correctly...
A manufacturer of chocolate chips would like to know whether its bag filling machine works correctly at the 447447 gram setting. It is believed that the machine is overfilling the bags. A 3131 bag sample had a mean of 455455 grams. Assume the population variance is known to be 900900. Is there sufficient evidence at the 0.10.1 level that the bags are overfilled? Step 5 of 6: Identify the level of significance for the hypothesis test.
A manufacturer of chocolate chips would like to know whether its bag filling machine works correctly...
A manufacturer of chocolate chips would like to know whether its bag filling machine works correctly at the 433433 gram setting. It is believed that the machine is underfilling the bags. A 4242 bag sample had a mean of 425425 grams. Assume the population variance is known to be 625625. A level of significance of 0.050.05 will be used. Find the P-value of the test statistic. You may write the P-value as a range using interval notation, or as a...
A manufacturer of chocolate chips would like to know whether its bag filling machine works correctly...
A manufacturer of chocolate chips would like to know whether its bag filling machine works correctly at the 447 gram setting. It is believed that the machine is overfilling the bags. A 31 bag sample had a mean of 455 grams. Assume the population variance is known to be 900. Is there sufficient evidence at the 0.1 level that the bags are overfilled? Step 4 of 6: Find the P-value of the test statistic. Round your answer to four decimal...
A manufacturer of chocolate chips would like to know whether its bag filling machine works correctly...
A manufacturer of chocolate chips would like to know whether its bag filling machine works correctly at the 412 gram setting. It is believed that the machine is underfilling the bags. A 8 bag sample had a mean of 404 grams with a standard deviation of 26 26 . A level of significance of 0.025 will be used. Assume the population distribution is approximately normal. Is there sufficient evidence to support the claim that the bags are underfilled?
A manufacturer of chocolate chips would like to know whether its bag filling machine works correctly...
A manufacturer of chocolate chips would like to know whether its bag filling machine works correctly at the 446 gram setting. based on a 21 bag sample where the mean is 442 grams and the standard deviation is 13, is there sufficient evidence at the 0.025 level that the bags are underfilled? assume the population distribution is approximately normal. final the value of the test statisc. round your anser to three decimal places.
A manufacturer of chocolate chips would like to know whether its bag filling machine works correctly...
A manufacturer of chocolate chips would like to know whether its bag filling machine works correctly at the 449 gram setting. It is believed that the machine is underfilling the bags. A 24 bag sample had a mean of 445 grams with a variance of 196. A level of significance of 0.1 will be used. Assume the population distribution is approximately normal. Determine the decision rule for rejecting the null hypothesis. Round your answer to three decimal places.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT