Question

A retailer, Continental Palms Retail (CPR), plans to create a database system to keep track of the information about its inventory.

CPR has several warehouses across the country. Each warehouse is uniquely named. CPR also wants to record the location, city, state, zip, and space (in cubic meters) of each warehouse. There are several warehouses in any single city.

CPR stores its products in the warehouses. A product may be stored in multiple warehouses. A warehouse may store multiple products. The quantity of a product in a warehouse needs to be recorded.

Every product has a unique UPC number. Other information about a product includes a name, a buying price, an approximate selling price, and a size (in cubic meters).

CPR also keeps track of the information about the manufacturers of products. Every product has a single manufacturer, but a manufacturer may manufacture multiple products. Each manufacturer has a unique name, an address (street, city, state, zip), and a contact phone number.

The requirements of CPR also indicate that there are the following full Functional Dependencies:

• UPC -> Name, Buying_Price, Selling_Price, Size, Manufacturer_Name, MStreet, MCity, MState, MZip, MPhone • Manufacturer_Name -> MStreet, MCity, MState, MZip, MPhone • Warehouse_Name -> WLocation, WCity, WState, WZip, WSpace • UPC, Warehouse_Name -> Quantity

A consulting company named Database Experts has designed the following relation data model for CPR. Product (UPC, Name, Buying_Price, Selling_Price, Size, Manufacturer_Name, MStreet, MCity, MState, MZip, MPhone, Warehouse_Name, WLocation, WCity, WState, WZip, WSpace, Quantity)

Although the designers at Database Experts claim that their design is superior in all aspects, CPR gives you a fair chance to justify your position. Now it’s your time to do the following.

(1) Show them what normal form their relation is in and why.

(2) Rescue their “bad” design using normalization. Decompose their relation Product into multiple smaller relations that are all in 3NF. Underline the primary key of each of your relations.

Answer 1

PLEASE GIVE IT A THUMBS UP, I SERIOUSLY NEED ONE, IF YOU NEED ANY MODIFICATION THEN LET ME KNOW, I WILL DO IT FOR YOU

1. The above connection is in 1st Normal Form since it permits just nuclear qualities.

2. The following is the chart of change of above table into third Normal structure tables according to the cycle. Underneath we can see the given table and afterward from this we determined second ordinary structure on the grounds that first typical structure decide is that it doesn't not have non-prime ascribes . so we partitioned into second .

The second is additionally isolated into third Normal structure since it is having transtive relationship. So at long last the standardized relations we get into as third typical structure.