Question

there were two unknown organic compounds. the first unknown was a solid that was white in color and was flaky like snow. the second unknown was a clear liquid. they were both tested in water, NaOH, HCl and H2SO4 to see if they dissolved. they both dissolved in the H2SO4.

First paragraph is a brief description of the physical attributes of the two unknowns. Then write a brief paragraph discussing the purpose of using solubility analysis on an unknown and how it works conceptually using IMAFs. Do not say "the goal of this lab" or " the purpose of this lab".

Answer 1

Solubility of both organic compounds was tested in water, NaOH, HCl they did not dissolve. Both dissolved in the H₂SO₄. So, both compounds may be alkene, alcohol, aldehyde or ketone. All organic compounds containing alkene functional groups or oxygen atoms are soluble in concentrated H₂SO₄. These functional groups react with H₂SO₄.to form new compounds. H₂SO₄ is a polar compound because its ions have dipole moments due to uneven charges. Both aldehydes and ketones are polar molecules because they contain carbon-oxygen double bond. They also have dispersion forces but no hydrogen bonding. Like dissolves like, so both compounds may be polar.

Sulfuric acid is a strong acid, so gives electrophile H⁺ and the alkene contains the pi-bond. So they react and alkenes are soluble in sulfuric acid. Alcohol is polar molecules because they contain -OH. They also have hydrogen bonding. So alcohol is soluble in sulfuric acid.