When 6M sodium hydroxide is added to an unknown white solid, the solid dissolves. What is...

When 6M sodium hydroxide is added to an unknown white solid, the solid dissolves. What is a possible identity for this solid? The options include: Mg(OH)2, Al2(SO4)3, BaCO3, and AgBr. Which one would the solid be and why?

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Expert Solution

sodium hydroxide NaOH is a strong base and it will reacts easily with acids.

Mg(OH)₂ is also a base and not completely soluble in water rather it forms a suspension called as molk of magnesia, it will not react with NaOH.

Al₂(SO₄)₃ is a salt of strong acid H2SO4 and weak base Al(OH)3 hence its aqueous solution is acidic, it is a white crystalline solid, the balanced chemical reaction is as follows

Al₂(SO₄)₃ + 6NaOH → 2Al(OH)₃ + 3Na₂SO₄

Barium carbonate BaCO₃ is insoluble in water and is also a weak base (all carbonates are weak bases due to carbonate-bicarbonate equilibrium exist in aqueous solutions).

Silver bromide (AgBr) is a salt of strong acid HBr and weak base AgOH. As AgOH is unstable it converts into silver oxide as 2AgOH --> Ag₂O + H₂O. Silver oxide is Black/ brown colored compound.

Final Answer: Al₂(SO₄)₃

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queen_honey_blossom answered 1 year ago

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