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In: Chemistry

Determine the volume of h2s (at 325k and 1.50 ATM) needed to produce 50.0g of s....

Determine the volume of h2s (at 325k and 1.50 ATM) needed to produce 50.0g of s. Asssume that there is excess so2 present.
2 H2S(g) + SO2(g) ---> 3S (s) + 2 H2O(g)

Solutions

Expert Solution

2 H2S(g) + SO2(g) ---> 3S (s) + 2 H2O(g)

3 moles of S produced from 2 moles of H2S

3*32g of S produced from 2*34g of H2S

50g of S produced from = 2*34*50/3*32    = 35.4 g of H2S

PV = nRT

n = W/M

molar mass of H2S (M) = 34g/mole

weight of H2S (W)          = 35.4g

                         T            = 325K

                        P             = 1.5atm

           PV   = WRT/M

             V   = WRT/PM

                   = 35.4*0.0821*325/1.5*34   = 18.52L >>>>answer

volume of H2S = 18.52L

queen_honey_blossom answered 2 years ago
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