Question

What is the output of the code below? After each line that has a cout, write what the output of the code is. See example in code below.

int i = 2, j = 1, k = i + j;

cout << k << endl; ➔ 3

double d = 2.99, e = 1, f = d + e;

cout << f << endl; double q = 1.50;

cout << q/3 << endl;

cout << 6.0/4 << endl;

char c = 65; int n = 65;

bool b = true;

if (b == true) cout << "b is true" << endl;

else cout << "b is not true" << endl;

if (c == n) cout << c << n << endl;

int i = 1.25, j = 1, k = i + j;

cout << k << endl;

cout << 1 / 3 << endl;

cout << 1 / 3.0 << endl;

char c = 'A'; c = c + 1;

int n = c; cout << c << n << endl;

Answer 1

Solution:

The output of the given code is provided below:

Explanation:

• All the values which are being displayed in the output screen are printed by the cout statement.
• The first output “3” is printed as the value of k by the statement cout << k << endl;
• The value of k is computed by the statement k = i + j and the value of i is 2 and j is 1.
• Hence, the value of k becomes 3 and displayed.
• The second value 3.99 is printed as the value of f by the statement cout << f << endl;
• The value of f is computed as f = d + e and the value of d = 2.99 and e is 1.
• Hence, the value of f is computed as 3.99 and displayed.
• The third and fourth output is printed by the following statements:

cout << q/3 << endl;

cout << 6.0/4 << endl;

• The value 0.5 is computed by q/3 and displayed.
• The value 1.5 is displayed after the computation of 6.0/4 by the cout statement.
• The next output as “b is true” is displayed by the statement cout << "b is true" << endl;
• Since the value of b is defined as a Boolean variable is true.
• So, with the condition as if (b == true), the condition becomes true and displays the statement “b is true”.
• The next output statement “A65” is displayed by the statement cout << c << n << endl;
• The value of c is defined as c = 65 and n = 65.
• Since the data type of the variable c is of type char and n is of type int.
• Therefore, the output of c is displayed as “A” whose ASCII value is 65, and the integer value of n is displayed as “65”.
• The next three output “2”, “0” and “0.333333” is displayed by the following three statements:

cout << k << endl;

cout << 1 / 3 << endl;

cout << 1 / 3.0 << endl;

• The value of k is updated as k = i + j where the value of i and j are redefined as 1.25 and 1.
• Therefore, the value of k is updated as 2.25.
• But the display value is only 2 because the type of k is int which is of integer type.
• If the type of k is defined as float, then it will display the entire value as 2.25.
• The output 0 is then displayed as the computation of 1/3.
• Since it is 1/3 so it is displaying only the integer value of this computation.
• When dividing 1 by 3, it would be 0.33333 but there is no floating-point either in 1 or 3, that why it is displaying only integer value as 0.
• In the next output, 0.333333 displayed as a floating value because 1/3.0 is having one floating-point value.
• The next output as “B66” is displayed by the following statement:

cout << c << n << endl;

• The value of c is defined as ‘A’ whose ASCII value is 65.
• Then the value of c is then get updated by adding 1 in it -> c = c+ 1.
• Therefore, the value of c becomes 66.
• After this, the value of c is copied to the value of n by the statement n = c.
• So, the value of n will get updated as 66.
• Since c is of type char thatswhy the character value of 66 is displayed which is B and the value of n which is of integer type is displayed as 66.
• Hence, the last output is “B66”.