In: Statistics and Probability
v
Consider the monthly time series shown in the table.
Month |
t |
Y |
January |
1 |
185 |
February |
2 |
192 |
March |
3 |
189 |
April |
4 |
201 |
May |
5 |
195 |
June |
6 |
199 |
July |
7 |
206 |
August |
8 |
203 |
September |
9 |
208 |
October |
10 |
209 |
November |
11 |
218 |
December |
12 |
216 |
The terms least squares and regression are used interchangeably. I have perforomed the regression analysis with 95% confidence and the output id attached in the below image
The Mode is E(Yt) = 2.730769 * t + 184
Question (b)
To get the sample for next two months substitute t as 13, 14 and get the respective E(Yt) values
For t =13
E(Y13) = 2.730769 * 13 + 184
= 219.5
= 220 rounded to 2 decimals
for t=14
E(Y14) = 2.730769 * 14 + 184
= 222.2307
= 222 rounded to zero decimals
Question (c)
THe forecasted values for nect 2 periods are 219.5 and 222
We have the Standard error from the Regression statistics as 3.223113
The forecast intervals are calculated by (forecasted value + (or) - Standard error)
So 95% forecast intervals for 13th month = (219.5 - 3.223113 , 219.5 + 3.223113)
= (216.276886, 222.7231)
= (216.28, 222.72) rounded to 2 decimals
So 95% forecast intervals for 14th month = (222.2307 - 3.223113 , 222.2307 + 3.223113)
= (219.007656, 225.4539)
= (219.01, 225.45) rounded to 2 decimals