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In: Chemistry

In Michaelis-Menten kinetics, what values would make an enzyme “good” at catalysis?

In Michaelis-Menten kinetics, what values would make an enzyme “good” at catalysis?

Solutions

Expert Solution

Let us consider an enzyme substrate reaction given below:

.............Eqn 1

Say rate constant for forward reaction is Kf and for backward step is Kr and rate constant for formation of the product is Kcat

Following the Michaelis-Menten kinetics the rate of the reaction will be given by the following equation:

.............Eqn 2

Where v is the rate of the reaction, vmax is the maximum rate of the reaction, [S] is the concentration of the substrate, [E]0 is the initial enzyme concentration, KM is the Michealis-Menten constant which is given by the following equation:

.............Eqn 3

So the values that makes the enzyme "good" at catalysis is:

1. KM: if the value of KM is lower then the rate of the reaction will be higher (See Eqn 2) which indicates high affinity of the substrate towards the enzyme which makes it a good catalyst. Actually KM is the substrate concentration at which the rate of the reaction is half of its maximum velocity (Consider KM=[S] and put it in Eqn 2). So lower KM value means at lower concentration of the substrate the reaction reaches high velocity. Now KM is independent the concentration or purity of an enzyme but dependent on both the enzyme and the substrate, as well as conditions such as temperature and pH.

2. Kcat: Higher Kcat means higher rate of product formation or high ternover number means higher number of substrate molecules converted to product per enzyme molecule per second.

3. Catalytic efficiency (Kcat/KM): this is a more sofisticated term as Kcat and KM both are interrelated (see Eqn 3). This is a measure of how efficient an enzyme is in converting a substrate into product.

4. If Kf is higher than the Kr then the reaction is favoured in the forward direction which facilates the formation of enzyme-substrate complex (ES).


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