Question

In: Statistics and Probability

Given n =1000, x = 841, Find a 95% confidence interval for the proportion 841/1000 =.841

Expert Solution

Solution :

Given that,

n = 1000

x = 841

Point estimate = sample proportion = = x / n = 841/1000=0.841

1 - = 1-0.841 =0.159

At 95% confidence level the z is ,

= 1 - 95% = 1 - 0.95 = 0.05

/ 2 = 0.05 / 2 = 0.025

Z/2 = Z0.025 = 1.96 ( Using z table )

Margin of error = E = Z/2 * $\sqrt$ ((( * (1 - )) / n)

= 1.96 ( $\sqrt$ ((0.841*0.159) /1000 )

E = 0.023

A 95% confidence interval for population proportion p is ,

- E < p < + E

0.841-0.023 < p <0.841+0.023

0.818< p < 0.864

(0.818 , 0.864)

orchestra answered 2 years ago

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Question

Given n =1000, x = 841, Find a 95% confidence interval for the proportion 841/1000 =.841

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