Question

If n=200 and X=60​, construct a 95​% confidence interval estimate for the population proportion. Round to five decimal points

Answer 1

sample success x =		60
sample size          n=		200
sample proportion p̂ =x/n=		0.3000
std error se= √(p*(1-p)/n) =		0.0324
for 95 % CI value of z=		1.960
margin of error E=z*std error   =		0.06351
lower bound=p̂ -E                       =		0.23649
Upper bound=p̂ +E                     =		0.36351

from above 95% confidence interval for population proportion =(0.23649 ,0.36351)