Question

In: Statistics and Probability

Find the margin of error for the 95% confidence interval used to estimate the population proportion.

Find the margin of error for the 95% confidence interval used to estimate the population proportion.

Solutions

Expert Solution

The formula of the margin of error(E) of the (1- )% confidence interval for the population proportion is as follow:

Where

is the sample proportion

n = sample size

if we have given the number of successes = x

then sample proportion is = = x/n

c = confidence level = 0.95

so that level of significance = = 1 - c = 1 - 0.95 = 0.05

this implies that /2 = 0.05/2 = 0.025

So we want to find such that


Therefore ,

The general excel command to find critical z value is

"=NORMSDIST(probability)"

Here probability = 0.975

So that critical is = "=NORMSINV(0.975)" = 1.96

Here we don't have the values of sample proportion ( ) and n

Let's assume that   = 0.70, and n = 50

So plugging the values in the formula of E, we get

So margin of error = E = 0.127

Note: You can use the given values of sample proportion and n to find the value of E.


Related Solutions

Determine the margin of error for a 95​% confidence interval to estimate the population proportion with...
Determine the margin of error for a 95​% confidence interval to estimate the population proportion with a sample proportion equal to 0.70 for the following sample sizes. a. nequals100             b. nequals200             c. nequals250 LOADING... Click the icon to view a portion of the Cumulative Probabilities for the Standard Normal Distribution table. a. The margin of error for a 95​% confidence interval to estimate the population proportion with a sample proportion equal to 0.70 and sample size nequals100 is nothing. ​(Round...
Determine the margin of error for a confidence interval to estimate the population proportion for the...
Determine the margin of error for a confidence interval to estimate the population proportion for the following confidence levels with a sample proportion equal to 0.36 and n=125. a. 90​%             b. 95​%             c. 98​% a. The margin of error for a confidence interval to estimate the population proportion for the 90% confidence level is _ b. The margin of error for a confidence interval to estimate the population proportion for the 95% confidence level is _ c. The margin of...
Determine the margin of error for a confidence interval to estimate the population proportion for the...
Determine the margin of error for a confidence interval to estimate the population proportion for the following confidence levels with a sample proportion equal to 0.45 and n equals=120. a. 90​% b. 95​% c. 99​%
Determine the margin of error for a confidence interval to estimate the population proportion for the...
Determine the margin of error for a confidence interval to estimate the population proportion for the following confidence levels with a sample proportion equal to .40 and n=100 A) 90% b) 95% c) 99%
Determine the margin of error for a confidence interval to estimate the population proportion for the...
Determine the margin of error for a confidence interval to estimate the population proportion for the following confidence levels with a sample proportion equal to 0.35 and n=120 a)90​% b)95​% c)98​% Click the icon to view a portion of the Cumulative Probabilities for the Standard Normal Distribution table. a. The margin of error for a confidence interval to estimate the population proportion for the 90 % confidence level is _____​(Round to three decimal places as​ needed.) b. The margin of...
Determine the margin of error for a 98​% confidence interval to estimate the population proportion with...
Determine the margin of error for a 98​% confidence interval to estimate the population proportion with a sample proportion equal to 0.80 for the following sample sizes. a. n equals125             b. n equals200             c. n equals250 The margin of error for a 98​% confidence interval to estimate the population proportion with a sample proportion equal to 0.80 and sample size n equals=125 is nothing
Determine the margin of error for a 99​% confidence interval to estimate the population proportion with...
Determine the margin of error for a 99​% confidence interval to estimate the population proportion with a sample proportion equal to 0.80 for the following sample sizes. a. n=100             b. n=200             c. n=260
Determine the point estimate of the population proportion, the margin of error for the following confidence interval
Determine the point estimate of the population proportion, the margin of error for the following confidence interval, and the number of individuals in the sample with the specified characteristic, x, for the sample size provided. Lower bound=0.226,upper bound=0.604,n=1200 The point estimate of the population is? round to the nearest thousandth as needed. the margin error is? round to the nearest thousandth as needed. the number of individuals in the sample with the specified characteristic is? round to the nearest integer...
Construct a 95​% confidence interval to estimate the population proportion with a sample proportion equal to...
Construct a 95​% confidence interval to estimate the population proportion with a sample proportion equal to 0.45 and a sample size equal to 120. ----- A 95% confidence interval estimates that the population proportion is between a lower limit of ___ and an upper limit of ___ ????
Assume that a sample is used to estimate a population proportion p. Find the 95% confidence...
Assume that a sample is used to estimate a population proportion p. Find the 95% confidence interval for a sample of size 252 with 79% successes. Enter your answer as a tri-linear inequality using decimals (not percents) accurate to three decimal places. < p <
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT