In: Statistics and Probability
World Happiness In a recent study on world happiness, participants were asked to evaluate their current lives on a scale from 0 to 10, where 0 represents the worst possible life and 10 represents the best possible life. The responses were normally distributed, with a mean of 5.4 and a standard deviation of 2.2. Find the probability that a randomly selected study participant’s response was (a) less than 4, (b) between 4 and 6, and (c) more than 8. Identify any unusual events in parts (a)–(c). Explain your reasoning.
a)
µ = 5.4
σ = 2.2
P( X ≤ 4 ) = P( (X-µ)/σ ≤ (4-5.4)
/2.2)
=P(Z ≤ -0.636 )
= 0.2623
......
b)
µ = 5.4
σ = 2.2
we need to calculate probability for ,
P ( 4 < X < 6
)
=P( (4-5.4)/2.2 < (X-µ)/σ < (6-5.4)/2.2 )
P ( -0.636 < Z <
0.273 )
= P ( Z < 0.273 ) - P ( Z
< -0.636 )
= 0.6075 - 0.2623
= 0.3452
.............
c)
µ = 5.4
σ = 2.2
P ( X ≥ 8.00 ) = P( (X-µ)/σ ≥ (8-5.4) /
2.2)
= P(Z ≥ 1.182 )
= P( Z < -1.182 )
= 0.1186 (answer)
.........
thanks