A flask contains 30.5 g of oxygen gas, 45.7 g of sulfur dioxide gas and 23.9...

A flask contains 30.5 g of oxygen gas, 45.7 g of sulfur dioxide gas and 23.9 g of fluorine gas. If the total pressure of the flask is 1.45 atm, what is the partial pressure of sulfur dioxide gas in the flask?

Expert Solution

moles of O2 = mass / molar mass

= 30.5 / 32

= 0.953

moles of SO2 = 45.7 / 64

= 0.714

moles of F2 = 23.9 / 38

= 0.629

mole fraction of SO2 = moles of SO2 / total moles

= 0.714 / (0.953 + 0.714 + 0.629)

= 0.311

partial pressure of = mole fraction x total pressure

= 0.311 x 1.45

= 0.451 atm

queen_honey_blossom answered 1 year ago

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