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When sodium hydroxide, NaOH, solution is added to Part B of the copper cycle, precipitate does...

When sodium hydroxide, NaOH, solution is added to Part B of the copper cycle, precipitate does not immediately form. What else is present in the reaction mixture from the first part of the cycle that causes this? Is it nitric acid?

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Expert Solution

The hydroxide ions (OH–) from the NaOH(aq) neutralize the excess hydronium ions (H3O+) left over from the previous part. Once all the H3O+ (HNO3 + H2O --> H3O+ + NO3-) ions are neutralized, additional OH– ions react with the Cu2+ complex ion to form a gelatinous blue Cu(OH)2 precipitate. Precipitate does not immediately form until all the H3O+ ions are neutralized. This can be understand pictorially as shown below.

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queen_honey_blossom answered 2 years ago
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