Question

In: Statistics and Probability

A pharmaceutical company claims that its new drug reduces systolic blood pressure. The systolic blood pressure...

A pharmaceutical company claims that its new drug reduces systolic blood pressure. The systolic blood pressure (in millimeters of mercury) for nine patients before taking the new drug and 22 hours after taking the drug are shown in the table below. Is there enough evidence to support the company's claim?

Let d=(blood pressure before taking new drug)−(blood pressure after taking new drug)d=(blood pressure before taking new drug)−(blood pressure after taking new drug). Use a significance level of α=0.01 for the test. Assume that the systolic blood pressure levels are normally distributed for the population of patients both before and after taking the new drug.

Patient 1 2 3 4 5 6 7 8 9
Blood pressure (before) 179 192 187 175 193 181 158 164 192
Blood pressure (after) 171 179 177 163 183 164 149 148

186

Step 1 of 5: State the null and alternative hypotheses for the test.

Step 2 of 5: Find the value of the standard deviation of the paired differences. Round your answer to one decimal place.

Step 3 of 5: Compute the value of the test statistic. Round your answer to three decimal places.

Step 4 of 5: Determine the decision rule for rejecting the null hypothesis H0. Round the numerical portion of your answer to three decimal places.

Step 5 of 5: Make the decision for the hypothesis test. Reject or Fail to Reject.

Solutions

Expert Solution

here, we will do paired t test

hypothesis:-

where , is the difference between blood pressure before taking new drug and blood pressure after taking new drug.

the necessary calculation table be:-

before() after()
179 171 8 10.38257
192 179 13 3.16057
187 177 10 1.49377
175 163 12 0.60497
193 183 10 1.49377
181 164 17 33.38297
158 149 9 4.93817
164 148 16 22.82737
192 186 6 27.27137
sum=101 sum=105.55556

number of observations(n) = 9

the value of the standard deviation of the paired differences be:-

the test statistic be:-

[ for more accurate calculation i have used the sd = 3.6324 in spite of 6.3]

degrees of freedom = (n-1) = (9-1) = 8

t critical value for df = 8,alpha=0.01, right tailed test be:-

[from t distribution table]

decision rule:-

reject the null hypothesis if,

decision:-

so, we reject the null hypothesis.

conclusion:-

there is sufficient evidence to support the claim that its new drug reduces systolic blood pressure at 0.01 level of significance.

*** if you have any doubt regarding the problem please write it in the comment box.if you are satisfied please give me a LIKE if possible..


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