Do you have food cravings? According to the New York Times, one of the largest studies of food cravings involved a survey of 1000 McMaster University students. The survey revealed that 97 % of the women in the study acknowledged specific food cravings while only 67 % of the men did. Assume that 600 of the respondents were women and 400 were men.

(a) Is there sufficient evidence to claim that the true proportion of women who acknowledge having food cravings exceeds the corresponding proportion of men? Test using α = .01.

(b) Why is it dangerous to conclude from the study that women have a higher incidence of food cravings than men?

The GSS 2014 respondents in the U.S. were asked, "How important do you think that being a Christian is for being truly American?" Responses were measured on a 4-point scale: 1=very important, 2=fairly important, 3=not very important, 4=not important at all. We will treat this variable as interval/ratio. Those with a high school degree had an average score of 2.35 (s = 1.21, n = 189). Those with a bachelor’s degree had an average score of 3.05 (s = 1.05, n = 61).

a)State the research and null hypothesis for a one-tailed significance test of means.

b) Calculate the t statistic

c) What is the critical value of t for our one-tailed test of the null hypothesis at the .05 level of significance?

d) If you had conducted a two-tailed test with alpha=.05, would your decision have been different?

A. In a two-tailed test, we would fail to reject the null hypothesis of no difference.

OR

B. In a two-tailed test, we would reject the null hypothesis of no difference.

1 20.8 1 20.4 1 25.1 1 27.4 1 15.4 1 15.3 1 13.9 2 16.3 2 14.5 2 10.4 2 12.2 2 12.5 2 9.5 2 15.3 3 16.8 3 20.9 3 28.4 3 22.5 3 17.5 3 14.9 3 22.4 3 17.5 3 25.4 3 22.4 4 16.7 4 14.5 4 13.7 4 15.4 4 12.4 4 16 4 7.5 4 12.9 4 18.3  Calculate a 95% confidence interval for the mean mileage of make 2. Use the method for single means when σ is not known, but use the Error Mean Square as the estimate of the variance. The degrees of freedom will be the Error DF, not n 1! Reminders: Confidence Interval = mean ± margin of error Margin of error = critical value * standard error Use critical value for T at /2 = 0.025 and df = error df (t table or EXCEL T.INV function) Use standard error = (error mean square/number of observations of that make of car) 10. What was the margin of error for the confidence interval for gasoline mileage of make 2?

11. What was the lower 95% confidence limit for make 2 mileage?

12. What was the upper 95% confidence limit for make 2 mileage?

 Conduct a test of hypothesis that the mean mileage of makes 2 and 3 do not differ. Use the method for single means when σ is not known with the Error MS serving as the pooled variance. Reminders: Test statistic t = difference of means / standard error of difference of means. The standard error of the difference equals square root of the sum of variances of the two means. The variance of each mean is estimated by the error mean square/number of observations in that mean.

13. What is the value of the t test statistic for testing the hypothesis that makes 2 and 3 do not differ in mileage?

To combat the novel coronavirus (COVID-10) pandemic, the Bloomington Pharmaceutical Co. Ltd. aggressively conducted a clinical trial with 8 patients for its new drug Remdiessivir. Patient’s health condition was evaluated before and after receiving the medication with a rating system in which 10 points represents complete recovery and 1 for being the worst condition. (a) Use the collected data below to assess the efficacy of the drug by conducting a hypothesis test at 5% significance level.

1. How many sherds/m³ would you expect to find at the source (e.g. x = 0)

2. How many sherds/m³ would you expect to find at a site located 18km from the kilns?  

3. Calculate the correlation coefficient for this data set (e.g. r)

Determine the proportion of the Revenue Growth data that lies within 1, 2, and 3 standard deviations of the mean. Determine, using the empirical rule, if the Revenue Growth data is approximately normally distributed.

Consider a binomial experiment with n=13 and p=0.3

a. Compute f(0) (to 4 decimals).

b. Compute f(8) (to 4 decimals).

c. Compute P(x<=2) (to 4 decimals).

d. Compute P(x>=4) (to 4 decimals).

e. Compute E(x) (to 1 decimal).

f. Compute Var(x) and ó.

Diagram and state whether the following syllogisms is valid

Some M are not P.

All M are S.

Some S are not P.

1. Some mistakes are not enduring tragedies. Therefore, no mistakes are enduring tragedies.

2. All married bachelors are polygamists. Therefore, it is false that some married bachelors are not polygamists.

3. No expensive lawsuits are friendly exchanges. Therefore, no unfriendly exchanges are inexpensive lawsuits.

A company wants to study the relationship between an employee's length of employment and their
number of workdays absent. The company collected the following information on a random sample of
seven employees.

Number of workdays absent 4,2,3 , 5, ,7 ,7 8
length of employment(in yrs) 10, 5, 9 , 2 , 2 ,2 0

1. in this problem whuch is the dependent variable, what is the correlation? and interpret its meaning.

what is the coefficient of determination? interpret its meaning

2. suposse you know that a person has worked for the company for 8 years. how many workdays would you predict he/ she would be absent?

3. Interpret in physical terms the meaning of slope in this example

A poll reported that only 375 out of a total of 1809 adults in a particular region said they had a​ "great deal of​ confidence" or​"quite a lot of​ confidence" in the public school system. This was down 5 percentage points from the previous year. Assume the conditions for using the CLT are met. Complete parts​ (a) through​(d) below.

1. Find a 95% confidence interval for the proportion that express a great deal of confidence or quite a lot of confidence in the public​ schools, and interpret this interval. (____,____) (3 decimal places)

2. We are Answer ____% confident that the population proportion of adults having a great deal or quite a lot of confidence in the public schools is between Answer ___ and ____.

3. Find an  80% confidence interval and interpret it. The 80% confidence interval for the proportion that express a great deal of confidence or quite a lot of confidence in the public schools is Answer  (____,____) (Round 3 decimal places)

4. Find the width of each interval by subtracting the lower proportion from the upper​ proportion, and state which interval is wider.The width of the 95% confidence interval is (Answer) ____ and the width of the 80% confidence interval is (Answer) ____ The 95% interval is wider. ​(Round to three decimal places as​ needed.)

The ideal (daytime) noise-level for hospitals is 45 decibels with a standard deviation of 9 db; which is to say, this may not be true. A simple random sample of 70 hospitals at a moment during the day gives a mean noise level of 47 db. Assume that the standard deviation of noise level for all hospitals is really 9 db. All answers to two places after the decimal.

(a) A 99% confidence interval for the actual mean noise level in hospitals is ________ db, ________ db.

(b) We can be 90% confident that the actual mean noise level in hospitals is ________ db with a margin of error of ________ db.

(c) Unless our sample (of 81 hospitals) is among the most unusual 2% of samples, the actual mean noise level in hospitals is between _______ db and ________ db.

(d) A 99.9% confidence interval for the actual mean noise level in hospitals is ________ db , ________ db .

(e) Assuming our sample of hospitals is among the most typical half of such samples, the actual mean noise level in hospitals is between _______ db and ________ db.

(f) We are 95% confident that the actual mean noise level in hospitals is ________ db, with a margin of error of _______ db .

(g) How many hospitals must we examine to have 95% confidence that we have the margin of error to within 1 db?

(h) How many hospitals must we examine to have 99.9% confidence that we have the margin of error to within 1 db?

Test the claim about the difference between two population means μ1 and μ2 at the level of significance alpha α. Assume the samples are random and​ independent, and the populations are normally distributed.

​Claim:  1μ1=2μ2​  alphaα=0.01

Population​ statistics 1σ1=3.33.3​, 2σ2=1.61.6

Sample​ statistics:x overbar 1x1=14, n1=29​, 2x2=16​, n2=28

Determine the standardized test statistic.

Determine P value

A restaurant chain that has 3 locations in Portland is trying to determine which of their 3 locations they should keep open on New Year’s Eve. They survey a random sample of customers at each location and ask each whether or not they plan on going out to eat on New Year’s Eve. The results are below. Run a test for independence to decide if the proportion of customers that will go out to eat on New Year’s Eve is dependent on location. Use α=0.05.

Can it be concluded that the choice to go out on New Year's Eve is dependent on restaurant location?

• A.

  No, it cannot be concluded that the choice to go out on New Year's Eve is dependent on restaurant location because the p-value = 0.8706

• B.

  Yes, it can be concluded that the choice to go out on New Year's Eve is dependent on restaurant location because the p-value = 0.8706

• C.

  Yes, it can be concluded that the choice to go out on New Year's Eve is dependent on restaurant location because the p-value = 0.1294.

• D.

  No, it cannot be concluded that the choice to go out on New Year's Eve is dependent on restaurant location because the p-value = 0.1294.

Construct the confidence interval for the population variance for the given values. Round your answers to one decimal place.

n=27, s2=9.2, and c=0.9