Question

In: Statistics and Probability

A restaurant chain that has 3 locations in Portland is trying to determine which of their...

A restaurant chain that has 3 locations in Portland is trying to determine which of their 3 locations they should keep open on New Year’s Eve. They survey a random sample of customers at each location and ask each whether or not they plan on going out to eat on New Year’s Eve. The results are below. Run a test for independence to decide if the proportion of customers that will go out to eat on New Year’s Eve is dependent on location. Use α=0.05.

NW Location

NE Location

SE Location

Will Go Out

66

40

45

Won’t Go Out

20

25

20

Can it be concluded that the choice to go out on New Year's Eve is dependent on restaurant location?

  • A.

    No, it cannot be concluded that the choice to go out on New Year's Eve is dependent on restaurant location because the p-value = 0.8706

  • B.

    Yes, it can be concluded that the choice to go out on New Year's Eve is dependent on restaurant location because the p-value = 0.8706

  • C.

    Yes, it can be concluded that the choice to go out on New Year's Eve is dependent on restaurant location because the p-value = 0.1294.

  • D.

    No, it cannot be concluded that the choice to go out on New Year's Eve is dependent on restaurant location because the p-value = 0.1294.

Solutions

Expert Solution

This is a test for independent between two categorical variables. So we will use chi-square dist.

Observed NW Location NE Location SE Location Total
Will Go Out 66 40 45 151
Won’t Go Out 20 25 20 65
Total 86 65 65 216
Expected NW Location NE Location SE Location Total
Will Go Out 60.12037 45.43981 45.43981 151
Won’t Go Out 25.87963 19.56019 19.56019 65
Total 86 65 65 216

Expected Value of a cell =R total * c total / overall total ...................... r = no. of rows and c = no. of columns

NW Location NE Location SE Location
Will Go Out 0.57501 0.65123 0.00426
Won’t Go Out 1.33580 1.51285 0.00989

Chi -square test STat =

Test Stat = 4.08904

c. df = (r -1) * (c -1) ...................... r = no. of rows and c = no. of columns

= 1* 2

df = 2

p - value = P( > T.S.)

= P( > 4.09) ....using chi -square dist tables

p-value = 0.129

Null hypo: The choice to go out on New Year's Eve is not dependent on restaurant location

Alternative hypo: The choice to go out on New Year's Eve is dependent on restaurant location

Since p-value > 0.05

We do not reject the null hypothesis

The choice and location are independent.

D.

No, it cannot be concluded that the choice to go out on New Year's Eve is dependent on restaurant location because the p-value = 0.1294.


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