In: Statistics and Probability
To combat the novel coronavirus (COVID-10) pandemic, the Bloomington Pharmaceutical Co. Ltd. aggressively conducted a clinical trial with 8 patients for its new drug Remdiessivir. Patient’s health condition was evaluated before and after receiving the medication with a rating system in which 10 points represents complete recovery and 1 for being the worst condition. (a) Use the collected data below to assess the efficacy of the drug by conducting a hypothesis test at 5% significance level.
8 | 7 |
9 | 9 |
3 | 6 |
4 | 6 |
2 | 7 |
7 | 5 |
4 | 10 |
8 | 6 |
(1) Null and Alternative Hypotheses
The following null and alternative hypotheses need to be tested:
Ho: μD = 0
Ha: μD ≠ 0
This corresponds to a two-tailed test, for which a t-test for two paired samples be used.
(2) Rejection Region
Based on the information provided, the significance level is α=0.05, and the degrees of freedom are df=7.
Hence, it is found that the critical value for this two-tailed test is tc=2.365, for \α=0.05 and df=7.
The rejection region for this two-tailed test is R={t:∣t∣>2.365}.
(3) Test Statistics
The t-statistic is computed as shown in the following formula:
(4) Decision about the null hypothesis
Since it is observed that ∣t∣=1.249≤tc=2.365, it is then concluded that the null hypothesis is not rejected.
Using the P-value approach: The p-value is p=0.2518, and since p=0.2518≥0.05, it is concluded that the null hypothesis is not rejected.
(5) Conclusion: It is concluded that the null hypothesis Ho is not rejected. Therefore, there is not enough evidence to claim that the population mean μ1 is different than μ2, at the 0.05 significance level. We don't have sufficient evidence to show that new drug Remdiessivir. has an effect at 0.05 level of significance.