In: Statistics and Probability
A campaign manager for a political candidate released a series of advertisements criticizing their opponent in an upcoming election. Their opponent previously had the support of 45% of voters, and the campaign manager wants to sample voters to test if support for their opponent has decreased. The manager surveyed 200 voters and the survey shows 40% support. Use .03 level of significance
Their opponent previously had the support of 45% of voters, and the campaign manager wants to sample voters to test if support for their opponent has decreased
p : Proporiton of voters who supported the opponent
To test whether p <0.45;
Null hypothesis : Ho : p =45/100 = 0.45
Alternate htypothesis : Ha : p < 0.45
Left tailed test
Given,
Hypothesized proportion : po = 0.45
Number of voters surveyed :sample size : n= 200
Sample Proportion of voters who supported the opponent : = 40/100 =0.40
Test Statistic:
For left tailed test :
As P-Value i.e. is greater than Level of significance i.e
(P-value:0.0776 > 0.03:Level of significance); Fail to Reject
Null Hypothesis
There is not sufficient evidence to conclude that the support for
their opponent has decreased.