In: Statistics and Probability
A researcher tests the effects of sleep deprivation on memory span (how many items (e.g., numbers) a person can keep in mind at once). Toward this end she recruits 5 participants. Each participant’s memory span is tested when normally rested (after waking from 8 hours of sleep), after being awake for 24 hours, and after being awake for 48 hours. The data are presented in the table below. Answer the following questions using an alpha of .05.
Well-Rested |
24 Hours Awake |
48 Hours Awake |
|
9 |
8 |
7 |
|
5 |
4 |
3 |
|
7 |
6 |
5 |
|
9 |
9 |
9 |
|
5 |
2 |
2 |
|
Mean |
7 |
5.8 |
5.2 |
What is the critical F value for this analysis?
3.84 |
||
4.46 |
||
6.04 |
||
19.00 |
Compare for the well rested and being awake.
Let well rested by S1^2 mean square error in this case degree of freedom is (5 - 1)= 4
And being awake is (awake 24 hr + awake 48 hours) Mean square is( S2^2 + S3^2) with degree of freedom 8
F critical value at (4, 8) for alpha 0.05 is 4.46 from table F table of alpha 0.05
Since option (B) is correct
Solution file is attached go through it
Thanks