In: Statistics and Probability
A factory that puts together car parts is known to produce 3% defective cars. Following a fire outbreak at the factory, reconstruction is carried out which may result in a change in the percentage of defective cars produced. To investigate this possibility, a random sample of 200 cars is taken from the production and a count reveals 14 defective cars. What may be concluded? Run a significance test using a 0.05 α-level of significance.
Solution:
p = 3% = 0.03
Claim : p is changed i,e p 0.03
The null and alternative hypothesis are
H0 : p = 0.03 vs Ha : p 0.03
n = 200
x = 14
Let be the sample proportion.
= x/n = 14/200= 0.07
The test statistic z is
z =
= (0.07 - 0.3)/[0.03*(1 - 0.03)/200]
= 3.32
3) p value
sign in H1 indicates that the test id "Two Tailed"
p value = 2 * P(Z < -3.32)
= 2 * 0.0005
= 0.0010
p value = 0.0010 is less than = 0.05
Reject H0 . There is sufficient evidence to conclude that a change in the percentage of defective cars produced.