Question

In: Statistics and Probability

There are 10 electric cars in a box and 3 are defective. Two electric cars are...

There are 10 electric cars in a box and 3 are defective. Two electric cars are selected without replacement. What is the chance of selecting 1 good electric car and 1 defective electric car?
Use a tree diagram & remember independent & dependent concept.
A) .25
B) .233
C) .47
D) .21

Solutions

Expert Solution

Solution:

Given: There are 10 electric cars in a box and 3 are defective. Thus 10-3 = 7 good car.

Two electric cars are selected without replacement

Let G = Good car and D = Defective car

We have to find:

P( 1 good electric car and 1 defective electric car) = ............?

P( 1 good and 2 defective) = P(First Good & Second Defective) + P( First Defective and Second Good)

P( 1 good and 2 defective) = 7/10 X 3/9 + 3/10 X 7/9

P( 1 good and 2 defective) = 0.2333 +0.2333

P( 1 good and 2 defective) = 0.4666

P( 1 good and 2 defective) = 0.47


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