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In a series R-L-C circuit, R= 360 ohm , L= 0.410 H and C= 1.1*10^-2 micro...

In a series R-L-C circuit, R= 360 ohm , L= 0.410 H and C= 1.1*10^-2 micro F. 1.What is the resonance angular frequency of the circuit? 2. The capacitor can withstand a peak voltage of 550 V. If the voltage source operates at the resonance frequency, what maximum voltage amplitude can it have if the maximum capacitor voltage is not exceeded?

Solutions

Expert Solution

The equation for the resonance angular frequency of the circuit is,

Here, is the inductance of the circuit and is the capacitance of the circuit.

Therefore, the angular frequency of the circuit is.

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(B)

At the resonanace, the impedance is given as,

Here, is the resistance of the circuit, is the inductive reactance, and is the capacitive reactance.

At the resonance,

Thus, the above equation changes as,

The maximum current is given as,

The maximum voltage across the capacitor is,

Rearrange the equation for .

$=\left (550 \textup{ V} \right )\left ( 360\Omega \right )\left\left (\left (1.49\times 10^{4} \textup{ rad/s} \right ) (1.1\times 10^{-8} \textup{ F} \right ) \right )$

Therefore, the maximum voltage amplitude that circuit can have is .

genius_generous answered 1 year ago

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