In: Economics
I've completed a-d, I need answers for E-H, please!
The demand for product Q is given...
I've completed a-d, I need answers for E-H, please!
The demand for product Q is given by Q = 385 - P and the
total cost of Q by: STC=3000+40Q-5Q^2 +(1/3)Q^3
- Find the price function and then the TR function. See
Assignment 3 or 4 for an example.
Q = 385 - P
P = 385 - Q
Total revenue (TR) = P x Q = 385Q -
Q2
- Write the MR and MC functions below. Remember: MR =
dTR/dQ and MC = dSTC/DQ. See Assignment 5 for a review of
derivatives.
MR = dTR/dQ = 385 - 2Q
MC = dSTC/dQ = 40 - 10Q + Q2
- What positive value of Q will maximize total
profit? Remember, letting MR = MC signals the objective
of total profit maximization. Solve MR = MC for Q. The value of Q
you get should not be zero or negative.
385 - 2Q = 40 - 10Q + Q2
Q2 - 8Q - 425 = 0
Q2 - 25Q + 17Q - 425 = 0
Q(Q - 25) + 17(Q - 25) = 0
(Q - 25) (Q + 17) = 0
Therefore, Q = 25, Q = -17
We dismiss Q=-17 because it is zero or negative, leaving
Q=25 will maximize total profit
- Use the price function found in (a) to determine the
price per unit that will need to be charged at the Q found in (c).
This will be the price you should ask for the total profit
maximizing quantity.
P = 385 - Q = 385 - 25 = 360
- What total profit will result from selling the quantity
found in (c) at the price found in (d)? Remember, profit is TR –
STC.
- At what level of Q is revenue maximized? Remember let
MR = 0 and solve for Q. MR = 0 signals the objective of maximizing
revenue.
- At what positive level of Q is marginal profit
maximized? You found the profit function in (e) above.
Marginal profit is the first derivative of the profit function (e).
Next, find the derivative of marginal profit, set it equal to zero,
and solve for Q.
- What price per unit should be charged at the quantity
found in (g)? Simply plug the Q you got in (g) into the same price
function you found in (a) and also used in (d).